coordinates

问题 I have a VCL form application with a tedit that will use FindVCLWindow (Mouse.CursorPos) to act upon a the control if it is beneath the mouse. When I left click on the tedit, my program returns nil for the result and the reason appears to be the mouse.curpos sent in the function. In my test I used a form size of 500+ x 500+ and located it at screen coordinates 100,100. The Tedit is located at 100,100 and is sized and displayed at 100,50. When I point at the edit, the mouse.curpos is returned

问题 I have implemented this example where I can zoom in to the given coordinates by clicking on the button. First , I want to be able to read coordinates out of a dynamic array, I tried by putting the array in the state but it fails. const ASPECT_RATIO = width / height; const LATITUDE = 37.78825; const LONGITUDE = -122.4324; const LATITUDE_DELTA = 0.0922; const LONGITUDE_DELTA = LATITUDE_DELTA * ASPECT_RATIO; const MARKERS = [ { latitude: 42.637368, longitude: 21.148682, }, { latitude: 42.604021,

问题 I am trying to calculate geodesic distance from a dataframe which consists of four columns of latitude and longitude data with around 3 million rows. I used the apply lambda method to do it but it took 18 minutes to finish the task. Is there a way to use Vectorization with NumPy arrays to speed up the calculation? Thank you for answering. My code using apply and lambda method: from geopy import distance df['geo_dist'] = df.apply(lambda x: distance.distance( (x['start_latitude'], x['start

问题 Ok, this might be a bit hard to explain since I can't include any video to show you what I mean, but I'll give it a shot. I have added a SKShapeNode to a scene and when I rotate the device orientation it follows along nicely as expected, positioning itself in the upper left side of the screen whichever way the device is rotated. But the SKShapeNode "lags" behind, that is, when I rotate to a new orientation, the node remain in the same position for half a second before it is relocated to the

问题 NSBundle *bundle = [NSBundle mainBundle]; NSString *pthpath = [bundle pathForResource:@"path" ofType:@"txt"]; NSString *content = [NSString stringWithContentsOfFile:pthpath encoding:NSUTF8StringEncoding error:nil]; array=[[NSArray alloc ]init]; array = [content componentsSeparatedByString:@"~"]; ===================================================================== here content is: 87,348~51,347~135,132~182,133~268,346~236,347~159,168~87,347@118,298~115,297~200,298~189,266~128,265~117,299@222

问题 I'm working on a code to do a software skinner (bone/skin animation), and I'm at the "optimization" phase (the skinner works pretty well and skin a 4900 triangles mesh with 22 bones in 1.09 ms on a Core Duo 2 Ghz (notebook)). What I need to know is : 1) Can someone show me the way (maybe with pseudocode) to transform a float3 (array of 3 float) (representing a coordinate) against a float4x3 matrix? 2) Can someone show me the way (maybe with pseudocode) to transform a float3 (array of 3 float)

问题 I'm working on a code to do a software skinner (bone/skin animation), and I'm at the "optimization" phase (the skinner works pretty well and skin a 4900 triangles mesh with 22 bones in 1.09 ms on a Core Duo 2 Ghz (notebook)). What I need to know is : 1) Can someone show me the way (maybe with pseudocode) to transform a float3 (array of 3 float) (representing a coordinate) against a float4x3 matrix? 2) Can someone show me the way (maybe with pseudocode) to transform a float3 (array of 3 float)

问题 I have a list of coordinates like this: [[(-88.99716274669669, 45.13003508233472), (-88.46889143213836, 45.12912220841379), (-88.47075415770517, 44.84090409706577), (-88.75033424251002, 44.84231949526811), (-88.75283245650954, 44.897062864942406), (-88.76794136151051, 44.898020801741716), (-88.77994787408718, 44.93415662283567), (-88.99624763048942, 44.93474749747682), (-88.99716274669669, 45.13003508233472)]] Or like this: [[(-88.99716274669669, 45.13003508233472)], [(-88.46889143213836, 45

问题 I have a list of coordinates like this: [[(-88.99716274669669, 45.13003508233472), (-88.46889143213836, 45.12912220841379), (-88.47075415770517, 44.84090409706577), (-88.75033424251002, 44.84231949526811), (-88.75283245650954, 44.897062864942406), (-88.76794136151051, 44.898020801741716), (-88.77994787408718, 44.93415662283567), (-88.99624763048942, 44.93474749747682), (-88.99716274669669, 45.13003508233472)]] Or like this: [[(-88.99716274669669, 45.13003508233472)], [(-88.46889143213836, 45

问题 I used below code from link to plot mouse position in axes(when mouse moving in axes) : point = get(gca, 'CurrentPoint'); % mouse click position camPos = get(gca, 'CameraPosition'); % camera position camTgt = get(gca, 'CameraTarget'); % where the camera is pointing to camDir = camPos - camTgt; % camera direction camUpVect = get(gca, 'CameraUpVector'); % camera 'up' vector zAxis = camDir/norm(camDir); upAxis = camUpVect/norm(camUpVect); xAxis = cross(upAxis, zAxis); yAxis = cross(zAxis, xAxis)