comparison

问题 I want make 2 different colors on the output image when using Imagemagick. I have an original image with "Hello World" in it. And a modified image with "Hello Warcraft" in the same area. The default compare command will give me a image and mark all the differences with red. Now I want to use 2 different colors like "orld" marked as red, and "arcraft" marked as another color, maybe blue. Is ImageMagick able to do this? If not, how to use ImageMagick to transfer a specified color to another one

问题 According to the specification: Interface values are comparable. Two interface values are equal if they have identical dynamic types and equal dynamic values or if both have value nil. var err error var reader io.Reader As far as understand, err and reader have different dynamic types ( error and io.Reader ) and therefore are not comparable. fmt.Println(err == reader) will cause a compile error: invalid operation: err == reader (mismatched types error and io.Reader) If it is true, why Println

问题 Why does the following happen with Python's lambdas (in both Python 2 and 3)? >>> zero = lambda n: n is 0 >>> zero(0) True >>> zero = lambda n: n is 0.0 >>> zero(0.0) False 回答1: The most common Python implementation store a number of small integers as "constant" or "permanent" objects in a pre-allocated array: see the documentation. So, these numbers can be recongized as identical objects using the is operator. This is not done for floats. If you were to compare the numbers using the equality

问题 In C/C++, switch/case compares only an integral type with a compile time constants. It's not possible to use them to compare user/library defined types like std::string with runtime values. Why the switch statement cannot be applied on strings? Can we implement look-a-like switch/case which gives similar syntactic sugar and serves the purpose of avoiding plain if/else comparisons. struct X { std::string s; bool operator== (const X& other) const { return s == other.s; } bool operator== (const

问题 I have the following list of vectors: a <- c(1,2,4,5,6,7,8,9) b <- c(1,2,4,5) c <- c(1,2,3,10,11,12,13,14) d <- c(1,2,3,10,15,16,17,18,19) e <- c(1,2,3,10,15,16) f <- list(a,b,c,d,e) Right now, I can do something like this is_subset <- vector() for(i in 1:length(f)) { is_subset <- c(is_subset, all(unlist(f[i]) %in% unlist(f[-i]))) } f[!is_subset] and get a list containing every vector that is not a subset of any other vector from the original list: [[1]] [1] 1 2 4 5 6 7 8 9 [[2]] [1] 1 2 3 10

问题 I'm trying to sort long numbers in ASC but seems that the comparison is wrong. There is a sequence of correct digits, but from the 7th digit it all messes up. Can anyone advise why? The classes: public class MyTime { private long timeInMicroSeconds; public MyTime (long timeInMicroSeconds) { this.timeInMicroSeconds = timeInMicroSeconds; } } public class tester implements Comparator<MyTime> { public int compare(MyTime o1, MyTime o2) { return (int) ( (-1) * (o2.getTimeInMicroSeconds() - o1

问题 I am writing some code in Python and I want to check if a list of words is in a long string. I know I could iterate through it multiple times and that may be the same thing but I wanted tp see if there is a faster way to do it. What I am currently doing is this: all_text = 'some rather long string' if "motorcycle" in all_text or 'bike' in all_text or 'cycle' in all_text or 'dirtbike' in all_text: print 'found one of em' but what I want to do is this: keyword_list = ['motorcycle', 'bike',

问题 I am writing some code in Python and I want to check if a list of words is in a long string. I know I could iterate through it multiple times and that may be the same thing but I wanted tp see if there is a faster way to do it. What I am currently doing is this: all_text = 'some rather long string' if "motorcycle" in all_text or 'bike' in all_text or 'cycle' in all_text or 'dirtbike' in all_text: print 'found one of em' but what I want to do is this: keyword_list = ['motorcycle', 'bike',

问题 When using Javascript promises, I ran into this weird behavior. Consider the following code: var Q = require('q'); var d1 = Q.defer(); var d2 = Q.defer(); compare(d1.promise, d2.promise); d1.resolve(3); d2.resolve(3); function compare(a, b) { Q.all([a,b]).then(function(results) { console.log('a: ' + a + ' b: ' + b); var result = (a == b)? 1: -1; console.log(result); }); } When you run this code, you get -1. I realize that I am not evaluating the results variable being passed in to the

问题 My version of pandas is: pd.__version__ '0.25.3' I have two dataframes , below is a sample, with the majority of the columns being the same across the two dataframes . I am trying to find the common columns , and create a new dataframe with all the common columns that shows their difference in values. A sample from c_r dataframe: Comp_name EOL - CL Per $ Access - CL Per $ Total Impact - CL Per $ Nike -0.02 -0.39 -0.01 Nike -0.02 -0.39 -0.02 Adidas -0.02 -0.39 -0.01 Adidas -0.02 -0.39 -0.02 A