children

Android GridLayout only shows last child

由 好久不见. 提交于 2020-01-16 01:09:20
问题 I am new to Android Development. I have been working with using a GridLayout to display Dynamically inserted ImageViews. My issue is located in "onFocusWindowChanged" but I pasted my onCreate where I do my assignments of the images. private List<Behavior> behaviors = null; private static int NUM_OF_COLUMNS = 2; private List<ImageView> images; private GridLayout grid; @Override protected void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout

JS高级---遍历DOM树

由 隐身守侯 提交于 2020-01-13 16:22:55
遍历DOM树 第一个函数: 给我根节点, 我会找到所有的子节点: forDOM(根节点) 获取这个根节点的子节点 var children=根节点的.children 调用第二个函数 第二个函数: 给我所有的子节点, 我把每个子节点的名字显示出来(children) for(var i=0;i<children.length;i++){ 每个子节点 var child=children[i]; f1(child); 给我节点, 我显示该节点的名字 child是子节点,但是如果child里面还有子节点,此时child就是爹了 child.children&&第一个函数(child) <!DOCTYPE html> <html lang="en"> <head> <meta charset="UTF-8"> <title>遍历DOM树</title> </head> <body> <h1>遍历 DOM 树</h1> <p style="color: green;">Tip: 可以在遍历的回调函数中任意定制需求</p> <div> <ul> <li>123</li> <li>456</li> <li>789</li> </ul> <div> <div> <span>haha</span> </div> </div> </div> <div id="demo_node"> <ul> <li

jQuery selectors performance

由 那年仲夏 提交于 2020-01-13 11:44:11
问题 I know I'm just being OCD about a few milliseconds worth of performance time, but I was just wondering why the following is true for me. It seems goes against my logic. I currently have a div that has fades out the image inside on hover: $('div.someclass').hover(function() { $(this).children('img').fadeOut(function(){ // do something }); }, function() { // do something }); After some testing, (looping through selectors 1000 times, taking the average of 9 tests) I have used 3 different

Last child forked will not die

由 拜拜、爱过 提交于 2020-01-13 10:13:31
问题 I have the main process forking two times and thus creating two children. The two children are piped with each other like this: ls | more Now the problem is that the second child never dies. Why is that? When does the last child in a pipe die really? Removing one wait() call shows the expected result of ls | more but gives some further weird behaviours(stuck terminal etc). Here is my code: int main(){ printf("[%d] main\n", getpid()); int pip[2], i; pipe(pip); /* CHILDREN*/ for (i=0; i<2; i++)

Last child forked will not die

由 好久不见. 提交于 2020-01-13 10:13:09
问题 I have the main process forking two times and thus creating two children. The two children are piped with each other like this: ls | more Now the problem is that the second child never dies. Why is that? When does the last child in a pipe die really? Removing one wait() call shows the expected result of ls | more but gives some further weird behaviours(stuck terminal etc). Here is my code: int main(){ printf("[%d] main\n", getpid()); int pip[2], i; pipe(pip); /* CHILDREN*/ for (i=0; i<2; i++)

jQuery模仿google的自动完成代码

由 為{幸葍}努か 提交于 2020-01-13 01:18:40
前端的html代码： Code <! DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd" > < html xmlns ="http://www.w3.org/1999/xhtml" > < head > < meta http-equiv ="Content-Type" content ="text/html; charset=utf-8" /> < title > jQuery autoConplete </ title > < script language ="javascript" src ="jquery.js" ></ script > < style type ="text/css" > * { margin : 0px ; padding : 0px ; } body { text-align : center ; padding-top : 100px ; font-size : 12px ; } table { margin : auto ; } #Keyword { width : 350px ; } div#content { position : relative ; }

CSS hover on a div, but not if hover on his children [duplicate]

由 ≡放荡痞女 提交于 2020-01-12 04:25:55
问题 This question already has answers here : How to apply child:hover but not parent:hover (5 answers) Closed 2 years ago . I looked if this question had already been answered, but couldn't find anything, only questions on the reverse css rule I am looking for. I have a div that contains one or more child, and I want it to change its background on hover, but not if hovering one of its children; I need the :hover rule to be restricted to pure element, not its offsprings it contains. Being not a

In JSF2, how to know if composite component has children?

由 杀马特。学长 韩版系。学妹 提交于 2020-01-11 05:29:08
问题 I'm writing a composite component, you have a special tag named: <composite:insertChildren /> Which inserts all the component's children there. Is there any way to know whether the component has children? Like a boolean value that could go on a "rendered" attribute. 回答1: The basic expression you're after is the following: #{cc.childCount} or more elaborately: #{component.getCompositeComponentParent(component).childCount} E.g. the following composite component: <html xmlns="http://www.w3.org

修改json数组中的键名

由 不想你离开。 提交于 2020-01-10 05:45:04
需求 // 更改前 newArr = [ { key : 1 , value : 10 } , { key : 2 , value : 20 } , { key : 3 , value : 30 } ] // 更改后 newArr = [ { name : 1 , value : 10 } , { name : 2 , value : 20 } , { name : 3 , value : 30 } ] 解决方法1 先将json数据转换为字符串，替换需要更改的键名，再转换为json数据 JSON . parse ( JSON . stringify ( t ) . replace ( /key/g , "name" ) ) 该方法简单粗暴，可用性较差 解决方法2 由于此时是使用传入的参数直接用于级联选择器，不愿意用递归进行遍历调用 //更改前传入的参数 orgid = [ { company : null id : "17c7c8b2f1f14c1eaa83fc9acee76be9" orgname : "极英科技" parentid : "0" children : [ ... ] devList : [ ] parentname : null } ] //更改后所需要用的参数 orgid = [ { company : null value :

获取jQuery对象的第一个子元素

由 吃可爱长大的小学妹 提交于 2020-01-06 14:57:24
<ul> <li>1</li> <li>2</li> <li>3</li> </ul> <script> console.log($('ul li:first')); console.log($("ul>li:first")); console.log($('ul').children('li').get(0)); console.log($('ul').children('li').eq(0)); console.log($('ul').children('li').first()); console.log($('ul').find('li').get(0)); console.log($('ul').find('li').eq(0)); console.log($('ul').find('li').first()); console.log($('ul').children(':first')); console.log($('ul').children('li:first')); console.log($('ul').children('li:first-child')); console.log($('ul').children('li:nth-child(1)')); console.log($('ul').find(':first')); console.log($
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