cell-array

A = {'A'; 'E'; 'A'; 'F'}; B = {'A';'B';'C';'D';'E'; 'F'}; I am trying to get for each string in cell array A , the index that matches that string in cell array B . A will have repeated values, B will not. find(ismember(B, A) == 1) outputs 1 5 6 but I want to get 1 5 1 6 preferably in a one liner. I can't use strcmp instead of ismember either as the vectors are different sizes. The vectors will actually contain date strings, and I need the index not a logical index matrix, I'm interested in the number not to use it for indexing. How do I do it? You flip the arguments to ismember , and you use

How to efficiently combined cell array vectors with different length into a matrix, filling the vectors to max length with 0s or NaNs? It would be a nice option for cell2mat() . For example, if I have C = {1:3; 1:5; 1:4}; I'd like to get either M = [1 2 3 0 0 1 2 3 4 5 1 2 3 4 0]; or M = [1 2 3 NaN NaN 1 2 3 4 5 1 2 3 4 NaN]; abcd EDIT: For a cell of row vectors as in your case, this will pad vectors with zeros to form a matrix out=cell2mat(cellfun(@(x)cat(2,x,zeros(1,maxLength-length(x))),C,'UniformOutput',false)) out = 1 2 3 0 0 1 2 3 4 5 1 2 3 4 0 A similar question was asked earlier today,

So, I have a cell-array of 1xN vectors of different lengths. I want to append them into a matrix so I can display them with imagesc . Obviously the matrix must be the width of the largest vector. My current code for this is below: tcell = {[1,2,3], [1,2,3,4,5], [1,2,3,4,5,6], [1], []}; lens = cellfun('length', tcell); rmat = NaN(length(tcell), max(lens)); for i = 1:length(tcell) rmat(i, 1:lens(i)) = tcell{i}; end Does anyone know a vectorized solution for this type of problem? I'm not really worried about the speed of this loop because of MATLAB's JIT. I'm just trying to expand my knowledge