ceil

1 #encoding:utf-8 2 import math 3 4 #向上取整 5 print "math.ceil---" 6 print "math.ceil(2.3) => ", math.ceil(2.3) 7 print "math.ceil(2.6) => ", math.ceil(2.6) 8 9 #向下取整 10 print "\nmath.floor---" 11 print "math.floor(2.3) => ", math.floor(2.3) 12 print "math.floor(2.6) => ", math.floor(2.6) 13 14 #四舍五入 15 print "\nround---" 16 print "round(2.3) => ", round(2.3) 17 print "round(2.6) => ", round(2.6) 18 19 #这三个的返回结果都是浮点型 20 print "\n\nNOTE:every result is type of float" 21 print "math.ceil(2) => ", math.ceil(2) 22 print "math.floor(2) => ", math.floor(2) 23 print "round(2) => ", round(2) 运行结果： 来源：

So I am adding and subtracting floats in javascript, and I need to know how to always take the ceiling of any number that has more than 3 decimal places. For example: 3.19 = 3.19 3.191 = 3.20 3.00000001 = 3.01 David Tang num = Math.ceil(num * 100) / 100; Though, due to the way floats are represented , you may not get a clean number that's to two decimal places. For display purposes, always do num.toFixed(2) . Actually I don't think you want to represent dollar amounts as float, due to the same reason cited by Box9. For example, 0.1*3 != 0.3 in my browser. It's better to represent them as

I have two questions regarding ceil() function.. The ceil() function is implemented in C. If I use ceil(3/2) , it works fine. But when I use ceil(count/2) , if value of count is 3, then it gives compile time error. /tmp/ccA4Yj7p.o(.text+0x364): In function FrontBackSplit': : undefined reference to ceil' collect2: ld returned 1 exit status How to use the ceil function in second case? Please suggest. How can I implement my own ceil function in C. Please give some basic guidelines. Thanks. The ceil() function is implemented in the math library, libm.so . By default, the linker does not link

关键词： B树 前言： （1）具体讲解之前，有一点，再次强调下：B-树，即为B树。因为B树的原英文名称为B-tree，而国内很多人喜欢把B-tree译作B-树，其实，这是个非常不好的直译，很容易让人产生误解。如人们可能会以为B-树是一种树，而B树又是一种树。而事实上是，B-tree就是指的B树。 （B树 <=> B-树）。引自： https://www.cnblogs.com/yfzhou/p/10290006.html （2）内节点：节点内嵌的节点 1、B树定义： 　　对于B树，我们一般描述成M（M>2）阶B树（这里的M阶指的是树的所有结点中的子树个数的最大值）。对于B树来说，它必须满足如下的性质： 　　 性质 ： 　　（1）节点的性质： 所有的叶子节点都在同一层； 每个节点由若干个指针和记录组成 。其中，每个节点中记录的个数比指针的个数少1个，指针将记录一一隔开。 　　（2）指针的性质： 每一个指针指向一个子节点； 每个节点最多有M个指针； 非叶子节点的根结点最少有两个分支； 叶子节点最少包含一个记录和两个空指针，叶节点的指针均为NULL； 非根非叶结点至少有ceil( M /2 )个分支；（ceil( M/2 )>=3）（分析：当这个值等于2，那么就变成二叉树；当这个值等于1，那么就变成链表。所以这个值必须大于等于3） 对于任意一个节点：ceil(M/2) <= d <= m

I want to make sure a float in PHP is rounded up if any decimal is present, without worrying about mathematical rounding rules. This function would work as follows: 1.1 to 2 1.2 to 2 1.9 to 2 2.3 to 3 2.8 to 3 I know the round() function exists but I don't see any function for rounding up if any decimal is found. Is there any easy way to do this? Use the ceil function: $number = ceil(1.1); //2 I know this is an old topic, however it appears in Google. I will extend Blake Plumb's answer regarding precision. ceil(1024.321 * 100) / 100; Multiplying by 100 and dividing by 100 only works with one

So I'm lucky enough to use Java 8 and the new time APi but I don't see any rounding functions... Basically if the time is... 2014-08-28T10:01.00.000 ----> 2014-08-28T10:02.00.000 2014-08-28T10:01.10.123 ----> 2014-08-28T10:02.00.000 2014-08-28T10:01.25.123 ----> 2014-08-28T10:02.00.000 2014-08-28T10:01.49.123 ----> 2014-08-28T10:02.00.000 2014-08-28T10:01.59.999 ----> 2014-08-28T10:02.00.000 This seems to be ok, but is it right? LocalDateTime now = LocalDateTime.now(Clock.systemUTC()); LocalDateTime newTime = now.plusMinutes(1); System.out.println(newTime.toString()); System.out.println

In JSTL, <fmt:formatNumber value="${1.6}" type="number" pattern="#"/> returns 2 and the following <fmt:formatNumber value="${1.4}" type="number" pattern="#"/> returns 1 and I need 2 , a ceiling of a number . Is there a direct way to achieve this in JSTL (or the only way to do so is by using an appropriate custom tag)? BalusC The default rounding mode of DecimalFormat that is used by <fmt:formatNumber> is RoundingMode.HALF_EVEN . There is no way to change that via any tag attribute. Just add 0.5 to the value when it's not an odd integer to make it to behave like RoundingMode.CEILING . <fmt

//public static double abs(double a) ：返回 double 值的绝对值。 double d1 = Math.abs(‐5); //d1的值为5 double d2 = Math.abs(5); //d2的值为5 //public static double ceil(double a) ：返回大于等于参数的最小的整数。 double d1 = Math.ceil(3.3); //d1的值为 4.0 double d2 = Math.ceil(‐3.3); //d2的值为 ‐3.0 double d3 = Math.ceil(5.1); //d3的值为 6.0 //public static double floor(double a) ：返回小于等于参数最大的整数。 double d1 = Math.floor(3.3); //d1的值为3.0 double d2 = Math.floor(‐3.3); //d2的值为‐4.0 double d3 = Math.floor(5.1); //d3的值为 5.0 public static long round(double a) ：返回最接近参数的 long。(相当于四舍五入方法) long d1 = Math.round(5.5); //d1的值为6.0 long d2 = Math.round