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问题 I have a matrix of 0-1. What I would like to do is to loop into this matrix and search for the 1. Each time a 1 has been found, to simply jump or pass that row, in order to only record 1 value per row. What I am trying to know if the first episode of the sequence is a 1 . I was thinking there might be a solution with break But I am unsure how to use it properly. So this is my first matrix SoloNight = structure(c(0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0,

问题 I have a matrix of 0-1. What I would like to do is to loop into this matrix and search for the 1. Each time a 1 has been found, to simply jump or pass that row, in order to only record 1 value per row. What I am trying to know if the first episode of the sequence is a 1 . I was thinking there might be a solution with break But I am unsure how to use it properly. So this is my first matrix SoloNight = structure(c(0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0,

问题 I have a matrix of 0-1. What I would like to do is to loop into this matrix and search for the 1. Each time a 1 has been found, to simply jump or pass that row, in order to only record 1 value per row. What I am trying to know if the first episode of the sequence is a 1 . I was thinking there might be a solution with break But I am unsure how to use it properly. So this is my first matrix SoloNight = structure(c(0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0,

问题 I'm trying to analyse a java code and see what it does, but in the "break label" line it gives the "Undefined label" error. from my understanding java unlike c# allows breaking into a scope outside of the current scope. isn't that right? if (conditions) { // some code if (conditions) { break label; } // some code } for (;;) { if (conditions) { // some code } // some code break; label: // some code } 回答1: In your example, you are trying to use break label; as though it were similar to the goto

问题 I came across this basic question, where switch case is used with string. Break statement is not used between cases but why it going to all the cases even when it is not matching the case string? So I'm curious to know why is the output 3 and not 1? public static void main(String [] args) { int wd=0; String days[]={"sun","mon","wed","sat"}; for(String s:days) { switch (s) { case "sat": case "sun": wd-=1; break; case "mon": wd++; case "wed": wd+=2; } } System.out.println(wd); } 回答1: You don't

问题 I came across this basic question, where switch case is used with string. Break statement is not used between cases but why it going to all the cases even when it is not matching the case string? So I'm curious to know why is the output 3 and not 1? public static void main(String [] args) { int wd=0; String days[]={"sun","mon","wed","sat"}; for(String s:days) { switch (s) { case "sat": case "sun": wd-=1; break; case "mon": wd++; case "wed": wd+=2; } } System.out.println(wd); } 回答1: You don't

问题 I came across this basic question, where switch case is used with string. Break statement is not used between cases but why it going to all the cases even when it is not matching the case string? So I'm curious to know why is the output 3 and not 1? public static void main(String [] args) { int wd=0; String days[]={"sun","mon","wed","sat"}; for(String s:days) { switch (s) { case "sat": case "sun": wd-=1; break; case "mon": wd++; case "wed": wd+=2; } } System.out.println(wd); } 回答1: You don't

问题 Why will the break not end the while true and return to the start? while True: print('This is a quiz') print('What is your name?') Name = input() print('Hello ' + Name + ', The quiz will now begin') import time time.sleep(2) question1 = "Question one: " answer1 = "True" and "true" print(question1) qanswer = input() if qanswer != answer1: print('Sorry, the answer is: ' + answer1) break if answer1 == qanswer: print("Correct! Here's the next question") I'm pretty new to python so I assume it's

问题 I have a csv-file, now i need to bring it in another form. I want to have a line break \r\n after a specific pattern. All patterns look like this: true or false; int number between 0 and 100; decimal number with two or three digits after the point; true or false; For example: false;2;23.987;false; true;0;8.37;false; false;8;166.987;false; and after the last semicolon, i want to have a line break. I am using notepad++. Thanks for your help 回答1: You may use \b(?:true|false);\d+;\d+\.\d+;(?:true

问题 I have a csv-file, now i need to bring it in another form. I want to have a line break \r\n after a specific pattern. All patterns look like this: true or false; int number between 0 and 100; decimal number with two or three digits after the point; true or false; For example: false;2;23.987;false; true;0;8.37;false; false;8;166.987;false; and after the last semicolon, i want to have a line break. I am using notepad++. Thanks for your help 回答1: You may use \b(?:true|false);\d+;\d+\.\d+;(?:true