backslash

strcat(dest, “\something”) - backslash not showing

孤人 提交于 2019-12-12 04:58:02
问题 I got a problem with C programming string concatenation. Why strcat(dest, "\something") will not have the backslash copied to dest ? You may wish to follow the example. #include <stdio.h> #include <stdlib.h> #include <string.h> int main() { char *dest = ""; char *test = "how \something"; dest = (char *)malloc((strlen(test) + 1) * sizeof(char)); strcat(dest, test); // Expect to see "how \something", but showed "how something" printf("%s\n", dest); free(dest); return 0; } 回答1: backslash not

xsi:schemaLocation backslash not allowed?

安稳与你 提交于 2019-12-11 19:28:37
问题 we are receiving an xml file that looks like this: <?xml version="1.0" encoding="UTF-8" standalone="yes"?> <AuditResponse xmlns="http://www.tibco.com/MFT/JMS-XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.tibco.com/MFT/JMS-XMLSchema C:\MFTIS\server\webapps\cfcc\WEB-INF/xsds/AuditResponse.xsd"> <ResponseType>TransferNotificationComplete</ResponseType> <NumRecords>1</NumRecords> <AuditRecord> <AuditType>InternetServer</AuditType> <AuditID

Why does ruby's JSON parser eat my backslash?

拜拜、爱过 提交于 2019-12-11 14:14:23
问题 The following example in JSON format contains one backslash, and if I run JSON.load , the backslash disappears: JSON.load('{ "88694": { "regex": ".*?\. (CVE-2015-46055)" } }') # => {"88694"=>{ "regex"=>".*?. (CVE-2015-46055)"}} How can I keep the backslash? My goal is to have this structure, and whenever I need, read the file, load the JSON into Hash, and search for those regular expressions. UPDATE 1 here is an example what I want. irb> "stack.overflow"[/.*?\./] => "stack." I can't pass the

Dictionary items not working when passed through powershell command

牧云@^-^@ 提交于 2019-12-11 10:48:30
问题 I have a dictionary created from a .txt file that contains desktop links. I need these links to be plugged in to a powershell command. However when I use '%s' % my_data[key] I get extra backslashes and therefore powershell will not process the command because it has no idea what to look for, how do I remove extra backslashes? ['powershell.exe', "$sh = New-Object -COM WScript.Shell\n$sh.CreateShortcut('C:\\Users\\johns\\desktop\\python\\Survey+Update\\testing this shared.lnk\n').TargetPath"]

How to append '\\?\' to the front of a file path in Python

谁都会走 提交于 2019-12-11 09:47:57
问题 I'm trying to work with some long file paths (Windows) in Python and have come across some problems. After reading the question here, it looks as though I need to append '\\?\' to the front of my long file paths in order to use them with os.stat(filepath). The problem I'm having is that I can't create a string in Python that ends in a backslash. The question here points out that you can't even end strings in Python with a single '\' character. Is there anything in any of the Python standard

replace apostrophe ' in the middle of the word with \' in java

牧云@^-^@ 提交于 2019-12-11 02:31:45
问题 I have an XPath //*[@title='ab'cd'] and I want to output it as //*[@title='ab\'cd'] I am using this code property = property.replaceAll("^[a-zA-Z]+(?:'[a-zA-Z]+)*", "\'"); but it is outputting //*[@text='ab'cd'] I couldn't find a similar question on StackOverflow.if there is please post the link in the comments. 回答1: To replace a ' in between two letters you need a (?<=\p{L})'(?=\p{L}) regex. A (?<=\p{L}) is a positive lookbehind that requires a letter immediately to the left of the current

How to replace backslash '\' with slash '/'?

試著忘記壹切 提交于 2019-12-11 01:02:39
问题 In my code I want to replace backslash character \ by a forward slash character / in a string. I've tried the following code: string str = chosen_file.Replace("/", @"\"); where, chosen_file is a string which contains numerous occurances of the \ character. But it doesn't seem to be working. Can I know any other solutions for this issue? 回答1: If you look at the definition of String.Replace: public string Replace( string oldValue, string newValue ) and your call: chosen_file.Replace("/", @"\");

How to use variable including special symbol in awk?

℡╲_俬逩灬. 提交于 2019-12-10 22:39:55
问题 For my case, if a certain pattern is found as the second field of one line in a file, then I need print the first two fields. And it should be able to handle case with special symbol like backslash. My solution is first using sed to replace \ with \\, then pass the new variable to awk, then awk will parse \\ as \ then match the field 2. escaped_str=$( echo "$pattern" | sed 's/\\/\\\\/g') input | awk -v awk_escaped_str="$escaped_str" '$2==awk_escaped_str { $0=$1 " " $2 " "}; { print } ' While

Backslash (\) behaving differently

狂风中的少年 提交于 2019-12-10 16:38:22
问题 I have small code as shown below public class Testing { public static void main(String[] args) { Scanner sc = new Scanner(System.in); String firstString = sc.next(); System.out.println("First String : " + firstString); String secondString = "text\\"; System.out.println("Second String : " + secondString); } } When I provide input as text\\ I get output as First String : text\\ Second String : text\ Why I am getting two different string when input I provide to first string is same as second

php regex replace double backslash with single

十年热恋 提交于 2019-12-10 16:27:48
问题 I do not want to use stripslashes() because I only want to replace "\\" with "\". I tried preg_replace("/\\\\/", "\\", '2\\sin(\\pi s)\\Gamma(s)\\zeta(s) = i\\oint_C \\frac{-x^{s-1}}{e^x -1} \\mathrm{d}x'); Which to my disapointment returns: 2\\sin(\\pi s)\\Gamma(s)\\zeta(s) = i\\oint_C \\frac{-x^{s-1}}{e^x -1} \\mathrm{d}x Various online regex testers indicate that the above should work. Why is it not? 回答1: First, like many other people are stating, regular expressions might be too heavy of