backslash

问题 I am facing some issues with escaping of back slash, below is the code snippet I have tried. Issues is how to assign a variable with escaped slash to another variable. var s = 'domain\\username'; var options = { user : '' }; options.user = s; console.log(s); // Output : domain\username - CORRECT console.log(options); // Output : { user: 'domain\\username' } - WRONG Why when I am printing options object both slashes are coming? I had feeling that I am doing something really/badly wrong here,

问题 I have string which contains few \ and I want to remove all of them. can anyone tell me how can I do that. I have already tried stringByReplacingOccurrencesOfString but it's not working out for me. 回答1: var str = "\\dagdahughuad\\dajughdaug" var str2 = str.stringByReplacingOccurrencesOfString("\\", withString: "", options: NSStringCompareOptions.LiteralSearch, range: nil) print(str2) This will output dagdahughuaddajughdaug 回答2: Converted above code in to SWIFT 3 var str = "\\dagdahughuad\

问题 I am trying to create a shell script with a simple functionality, but it seems I can not wrap my head about how to handle backslashes correctly. One of my functions look like this: #!/bin/sh func() { cmd="$*" printf "%s\n" "$cmd" echo -e $cmd } func '%{NAME}\\n' This is the correct output, as I need it: %{NAME}\\n %{NAME}\n Now the problem is, I can not use "echo -e", as this script needs to be run on *nix system, where the echo command does not have the "-e" flag (HPUX for instance), that

问题 I'm trying to split a string "\b1\c1\d1" into ["","b1","c1","d1"] ; But even with string.split("\\") (and all ways that internet says) it simply give me a ["1c1d1"] ; How can I get the result I want? 回答1: Worked for me this way. Tested on chrome console: var x = "\b1\c1\d1"; // results in "1c1d1" var x = "\\b1\\c1\\d1"; // results in "b1\c1\d1" var y = x.split("\"); VM160:2 Uncaught SyntaxError: Unexpected token ILLEGAL(…)InjectedScript._evaluateOn @ VM101:875InjectedScript._evaluateAndWrap @

问题 java.lang.RuntimeException: NotImplemented at org.apache.poi.hssf.usermodel.HSSFPatriarch.createChart(HSSFPatriarch.java:518) Drawing drawing = sheet.createDrawingPatriarch(); ClientAnchor anchor = drawing.createAnchor(0, 0, 0, 0, 0, 5, 8, 20); Chart chart = drawing.createChart(anchor); // Error got here i am using jar file poi-3.11-beta2.jar 来源： https://stackoverflow.com/questions/42154420/java-lang-runtimeexception-notimplemented-at-org-apache-poi-hssf-usermodel-hssf

问题 I'm trying to get values from server by parsing the xml data returned through the websevice. the code used for parsing is below -(void) parser:(NSXMLParser *)parser didStartElement:(NSString *)elementName namespaceURI:(NSString *)namespaceURI qualifiedName:(NSString *)qName attributes:(NSDictionary *)attributeDict { rValue= @""; isTag = FALSE; if ([elementName caseInsensitiveCompare:@"BusinessName"] == NSOrderedSame) isTag=YES; } -(void) parser:(NSXMLParser *)parser foundCharacters:(NSString

问题 I have a bunch of string with special escape codes that I want to store unescaped- eg, the interpreter shows "\\014\"\\000\"\\016smoothing\"\\011mean\"\\022color\"\\011zero@\\016" but I want it to show (when inspected) as "\014\"\000\"\016smoothing\"\011mean\"\022color\"\011zero@\016" What's the method to unescape them? I imagine that I could make a regex to remove 1 backslash from every consecutive n backslashes, but I don't have a lot of regex experience and it seems there ought to be a

问题 I am using a backslash as an escape character for a serialization format I am working on. I have it as a constant but IntelliJ is underlining it and highlighting it red. On hover it gives no error messages or any information as to why it does not like it. What is the reason for this and how do I fix it? 回答1: IntelliJ is smarter than I am and realised that I was using this character in a regular expression where 2 backslashes would be needed, however, IntelliJ also assumed that my puny mind

问题 How can I compare if a backslash is in my string? I don't know how to write the backslash symbol to compare it. I try this but don't work: Code: s = r"\"" print s Output: \" If I try s = "\"" it gives " as output I don't know how to acheive that. Thanks for any help. 回答1: You need to escape the backslash. s = "\\" 回答2: >>>mystring = "can python find this backslash \n" >>>"\\" in r"%r" % mystring True while trying to filter the backslash \ character from being used in Windows filenames I

问题 I understand that current best practice for line continuation is to use implied continuation inside parenthesis. For example: a = (1 + 2 + 3 + 4) From PEP8 (https://www.python.org/dev/peps/pep-0008/): The preferred way of wrapping long lines is by using Python's implied line continuation inside parentheses, brackets and braces. Long lines can be broken over multiple lines by wrapping expressions in parentheses. These should be used in preference to using a backslash for line continuation. I