area

问题 I have 4 coordinates of area: x1,y1 ... etc. And have one more position x0,y0 . How to check if my coordinate in selected area? 回答1: I will explain you how to check that (x0,y0) lies "below" the line through (x1,y1) and (x2,y2). Essentially, you want that the vector (x0-x1,y0-y1) points "to the right" of (x2-x1, y2-y1). This is equivalent to saying that the matrix x0-x1 y0-y1 x2-x1 y2-y1 has a negative determinant. So your condition becomes (x0-x1)(y2-y1) < (y0-y1)(x2-x1). You get such a

问题 I'm trying to figure out how to calculate the water filled area of a river cross section for different water levels. For the cross-section I have the depth at every 25 cm over the 5 m wide river and the area can be calculated based on a nicely answered previous question Calculate area of cross section for varying height x_profile <- seq(0, 500, 25) y_profile <- c(50, 73, 64, 59, 60, 64, 82, 78, 79, 76, 72, 68, 63, 65, 62, 61, 56, 50, 44, 39, 25) library(sf) #Create matrix with coordinates m <

问题 I have a set of point which represent a self intersecting polygon.I am able to find the intersection point.But i am unable to split this polygon into smaller polygon which is not self intersection.Any idea how to do that.I am using vb 2008 .I need this to calculate the area of self intersecting polygon.Thank you 回答1: There is quite a bit known about this problem. In fact, there are earlier similar questions here on SO, e.g., "Divide self intersecting polygon (C Code)." Here is a Master's

问题 I have a complex area chart, which uses some stacked and some unstacked series. Prior to version 3, everything worked fine. With version 3, there are some odd buggy behaviors, in both firefox and chrome: Example here: http://jsfiddle.net/jlbriggs/yj3FP/ stacking:'normal', If I disable stacking, everything looks as expected. But I need stacking. So, if you comment out the 'stacking:normal' line, you will see the chart as it should be, except for the stacking part... In the example linked to

问题 Let say we have TRMM precipitation data, each file represents data for each month. For example, the files in the folder are: 3B42.1998.01.01.7A.nc, 3B42.1998.02.01.7A.nc, 3B42.1998.03.01.7A.nc, 3B42.1998.04.01.7A.nc, 3B42.1998.05.01.7A.nc, ...... ...... 3B42.2010.11.01.7A.nc, 3B42.2010.12.01.7A.nc. These files having a dimension as follows : Xsize=1440, Ysize=400, Zsize=1,Tsize=1. Longitude set to 0 to 360 and Latitude set to -50 to 50. I want to calculate the amount of precipitation over a

问题 Let say we have TRMM precipitation data, each file represents data for each month. For example, the files in the folder are: 3B42.1998.01.01.7A.nc, 3B42.1998.02.01.7A.nc, 3B42.1998.03.01.7A.nc, 3B42.1998.04.01.7A.nc, 3B42.1998.05.01.7A.nc, ...... ...... 3B42.2010.11.01.7A.nc, 3B42.2010.12.01.7A.nc. These files having a dimension as follows : Xsize=1440, Ysize=400, Zsize=1,Tsize=1. Longitude set to 0 to 360 and Latitude set to -50 to 50. I want to calculate the amount of precipitation over a

问题 I have an arbitray area and want to extract a path (series of pixels). The path should start and end so that you walk the longest way but always stay in the center, between your borders. Is there any sensible way to implement this in opencv? Basically a morphologic filter like erosion (to find the middle between the borders) sounds good. However I do not want to shorten the the length of the path. It does not need to be a fully automatic solution. User input, e.g. marking the start and end

问题 I,m trying to draw a polygon shape of any kind using multiple vertices with path2d and I want to later on see if a determinate point is within its area using java.awt.geom.Area public static boolean is insideRegion(Region region, Coordinate coord){ Geopoint lastGeopoint = null; GeoPoint firstGeopoint = null; final Path2D boundary = new Path2D.Double(); for(GeoPoint geoponto : region.getGeoPoints()){ if(firstGeopoint == null) firstGeopoint = geoponto; if(lastGeopoint != null){ boundary.moveTo

问题 I've been using the following code to detect browser client area width for ages and it wokred 100% with all browsers, including FF, Safari and various versions of IE. However, now when I switched to a new monitor with widescreen resolution (1280x800) this code fails on IE8. It reports clientwidth of 1024 !!!??? Any ideas how to get the correct client area width ? function getClientWidth() { var v=0,d=document,w=window; if((!d.compatMode || d.compatMode == 'CSS1Compat') && !w.opera && d

问题 I can use this to set a text area (selectedtext) value in a form (submitquestion) if Firefox, but it fails in IE. document.submitquestion.selectedtext.value = txt; 回答1: This should work: <textarea id="bla">from</textarea> <script type="text/javascript"> document.getElementById("bla").value = "test"; </script> 回答2: Try this: document.forms['submitquestion'].elements['selectedtext'].value = txt; Assuming you have: <form name='submitquestion'> <textarea name='selectedtext'></textarea> </form>