apache-commons-codec

How to decode JWT (Header and Body) in java using Apache Commons Codec?

南楼画角 提交于 2021-02-17 08:39:31
问题 I am looking decode the following JWT using Apache Commons Codec . How we can do that ? eyJhbGciOiJIUzI1NiJ9.eyJzdWIiOiJ0ZXN0Iiwicm9sZXMiOiJST0xFX0FETUlOIiwiaXNzIjoibXlzZ WxmIiwiZXhwIjoxNDcxMDg2MzgxfQ.1EI2haSz9aMsHjFUXNVz2Z4mtC0nMdZo6bo3-x-aRpw This should retrieve Header , Body and Signature part. Whats the code ? 回答1: Here you go: import org.apache.commons.codec.binary.Base64; @Test public void testDecodeJWT(){ String jwtToken = "eyJhbGciOiJIUzI1NiJ9

commons http client - kerberos token while negotiating has \r\n (carriage return line feed) characters

不羁岁月 提交于 2020-01-04 11:09:18
问题 I am trying to use jakarta commons http client. Doing kerberos authentication to communicate with a server. Authentication always fails. On digging deeper I found out that the kerberos token header has carriage return line feed characters in it which is the root cause of the issue. Why does it have \r\n characters and why is that an issue? 回答1: \r\n characters in the kerberos token is an issue because \r is an HTTP control characters. That essentially means that the server only sees first

commons http client - kerberos token while negotiating has \r\n (carriage return line feed) characters

柔情痞子 提交于 2020-01-04 11:09:04
问题 I am trying to use jakarta commons http client. Doing kerberos authentication to communicate with a server. Authentication always fails. On digging deeper I found out that the kerberos token header has carriage return line feed characters in it which is the root cause of the issue. Why does it have \r\n characters and why is that an issue? 回答1: \r\n characters in the kerberos token is an issue because \r is an HTTP control characters. That essentially means that the server only sees first

Denodo Jar get conflicts with Play Framework Jar

一笑奈何 提交于 2019-12-24 22:02:09
问题 I am using : Latest version of play framework wi.-> 2.3.5 Latest version of Denodo -> 5.5 win Denodo is using Apache Common Codec 1.3 whereas Play is using few new methods introduced in Apacahe Common Codec 1.4 (E.g. Caused by: java.lang.NoSuchMethodError: org.apache.commons.codec.digest.DigestUtils.sha1Hex(Ljava/lang/String;)Ljava/lang/String; ). Somehow denodo's legacy jar is getting preference over play's jar. Is there any way to get rid of this situation? 回答1: Instead of using the denodo

Unexpected results from Metaphone algorithm

廉价感情. 提交于 2019-12-24 12:17:48
问题 I am using phonetic matching for different words in Java. i used Soundex but its too crude. i switched to Metaphone and realized it was better. However, when i rigorously tested it. i found weird behaviour. i was to ask whether thats the way metaphone works or am i using it in wrong way. In following example its works fine:- Metaphone meta = new Metaphone(); if (meta.isMetaphoneEqual("cricket","criket")) System.out.prinlnt("Match 1"); if (meta.isMetaphoneEqual("cricket","criketgame")) System

Base64-encode a file and compress it

丶灬走出姿态 提交于 2019-12-22 06:58:41
问题 My goal is to encode a file and zip it in a folder in java. I have to use the Apache's Commons-codec library. I am able to encode and zip it and it works fine but when i decode it back to its original form, it looks like the file has not completely been encoded. Looks like a few parts are missing. Can anybody tell me why this happens? I am also attaching the part of my code for your reference so that you can guide me accordingly. private void zip() { int BUFFER_SIZE = 4096; byte[] buffer =

How to convert sun.misc.BASE64Encoder to org.apache.commons.codec.binary.Base64

天涯浪子 提交于 2019-12-22 04:19:20
问题 I have the following code for sun.misc.BASE64Encoder : BASE64Decoder decoder = new BASE64Decoder(); byte[] saltArray = decoder.decodeBuffer(saltD); byte[] ciphertextArray = decoder.decodeBuffer(ciphertext); and would like to convert it to org.apache.commons.codec.binary.Base64 . I've gone through the APIs, the docs, etc., but I can't find something that seems to match and give the same resulting values. 回答1: It's actually almost the exact same: Base64 decoder = new Base64(); byte[] saltArray

Showing Base64String Image with Thymeleaf

徘徊边缘 提交于 2019-12-10 03:10:48
问题 I am storing jpg images in a database (as byte array). I want to avoid dropping onto filesystem before showing on a web page. Unit Tests show that database storage and retrieval are working without corruption. Fies can be extracted from database and converted back to jpg file The image was converted to bytearray and stored in database with the following code: public static byte[] getImageAsBytes(BufferedImage buffer) throws IOException { ByteArrayOutputStream baos = new ByteArrayOutputStream(

org.apache.commons.codec.digest.Md5Crypt.md5Crypt function. exception occured under linux, but fine under windows

十年热恋 提交于 2019-12-09 03:58:54
问题 We are using commons-codec to encrypt passwords, using the org.apache.commons.codec.digest.Md5Crypt.md5Crypt function. It works fine on a Windows environment, but on CentOS, an exception is thrown. We have 3 centOS test servers: one is centOS7, one is centOS6.7, and one is centOS7 minimal. The weirdest thing is, the code works on the centOS7 server, but not on the other two. The only difference between them is the OS. Same tomcats, same jdks, same builds. Does it need any other things under

Base64-encode a file and compress it

ⅰ亾dé卋堺 提交于 2019-12-05 09:49:40
My goal is to encode a file and zip it in a folder in java. I have to use the Apache's Commons-codec library. I am able to encode and zip it and it works fine but when i decode it back to its original form, it looks like the file has not completely been encoded. Looks like a few parts are missing. Can anybody tell me why this happens? I am also attaching the part of my code for your reference so that you can guide me accordingly. private void zip() { int BUFFER_SIZE = 4096; byte[] buffer = new byte[BUFFER_SIZE]; try { // Create the ZIP file String outFilename = "H:\\OUTPUT.zip";