addition

I have the methods that do both the multiplication and addition, but I'm just not able to get my head around them. Both of them are from external websites and not my own: public static void bitwiseMultiply(int n1, int n2) { int a = n1, b = n2, result=0; while (b != 0) // Iterate the loop till b==0 { if ((b & 01) != 0) // Logical ANDing of the value of b with 01 { result = result + a; // Update the result with the new value of a. } a <<= 1; // Left shifting the value contained in 'a' by 1. b >>= 1; // Right shifting the value contained in 'b' by 1. } System.out.println(result); } public static

A fairly simple question. What's the difference between: $merged = array_merge($array1, $array2); and $merged = $array1 + $array2; ? The difference is: The + operator takes the union of the two arrays, whereas the array_merge function takes the union BUT the duplicate keys are overwritten). Yehosef Here's a simple illustrative test: $ar1 = [ 0 => '1-0', 'a' => '1-a', 'b' => '1-b' ]; $ar2 = [ 0 => '2-0', 1 => '2-1', 'b' => '2-b', 'c' => '2-c' ]; print_r($ar1+$ar2); print_r(array_merge($ar1,$ar2)); with the result: Array ( [0] => 1-0 [a] => 1-a [b] => 1-b [1] => 2-1 [c] => 2-c ) Array ( [0] => 1

If I have list=[1,2,3] and I want to add 1 to each element to get the output [2,3,4] , how would I do that? I assume I would use a for loop but not sure exactly how. new_list = [x+1 for x in my_list] >>> mylist = [1,2,3] >>> [x+1 for x in mylist] [2, 3, 4] >>> list-comprehensions python . The other answers on list comprehension are probably the best bet for simple addition, but if you have a more complex function that you needed to apply to all the elements then map may be a good fit. In your example it would be: >>> map(lambda x:x+1, [1,2,3]) [2,3,4] if you want to use numpy there is another

A friend and I are going back and forth with brain-teasers and I have no idea how to solve this one. My assumption is that it's possible with some bitwise operators, but not sure. CMS In C, with bitwise operators: #include<stdio.h> int add(int x, int y) { int a, b; do { a = x & y; b = x ^ y; x = a << 1; y = b; } while (a); return b; } int main( void ){ printf( "2 + 3 = %d", add(2,3)); return 0; } XOR ( x ^ y ) is addition without carry. (x & y) is the carry-out from each bit. (x & y) << 1 is the carry-in to each bit. The loop keeps adding the carries until the carry is zero for all bits. ackb

I feel embarrassed asking this, but how do you adjust a single value within a tensor? Suppose you want to add '1' to only one value within your tensor? Doing it by indexing doesn't work: TypeError: 'Tensor' object does not support item assignment One approach would be to build an identically shaped tensor of 0's. And then adjusting a 1 at the position you want. Then you would add the two tensors together. Again this runs into the same problem as before. I've read through the API docs several times and can't seem to figure out how to do this. Thanks in advance! UPDATE: TensorFlow 1.0 includes a

This question already has an answer here: How to force JS to do math instead of putting two strings together 9 answers I'm trying to add all of the calorie contents in my javascript like this: $(function() { var data = []; $( "#draggable1" ).draggable(); $( "#draggable2" ).draggable(); $( "#draggable3" ).draggable(); $("#droppable_box").droppable({ drop: function(event, ui) { var currentId = $(ui.draggable).attr('id'); var total = 0; data.push($(ui.draggable).attr('id')); if(currentId == "draggable1"){ var myInt1 = parseFloat($('#MealplanCalsPerServing1').val()); } if(currentId == "draggable2"

i want to add two date intervals to calculate the total duration in hours and minutes in fact i want to perform addittion as shown below: $a = new DateTime('14:25'); $b = new DateTime('17:30'); $interval1 = $a->diff($b); echo "interval 1 : " . $interval1->format("%H:%I"); echo "<br />"; $c = new DateTime('08:00'); $d = new DateTime('13:00'); $interval2 = $c->diff($d); echo "interval 2 : " . $interval2->format("%H:%I"); echo "<br />"; echo "Total interval : " . $interval1 + $interval2; Any idea how to perform this type of interval addition to get the sum of the two intervals in total hours and