addition

How do I cycle through the entire alphabet with Swift while assigning values?

由 感情迁移 提交于 2019-11-28 08:32:15
问题 I am trying to cycle through the entire alphabet using Swift. The only problem is that I would like to assign values to each letter. For Example: a = 1, b = 2, c = 3 and so on until I get to z which would = 26. How do I go through each letter in the text field that the user typed while using the values previously assigned to the letters in the alphabet? After this is done, how would I add up all the letters values to get a sum for the entire word. I am looking for the simplest possible way to

Help in double precision addition

由 喜夏-厌秋 提交于 2019-11-28 07:36:03
问题 I was testing some of my code, in javascript I added .1+.2 and it gives me .30000000000000004 instead of .3 . I don't understand this. But when I added .1+.3 it gives me .4. I googled it and find its something about Double Precision addition. But I don't know what it is. 回答1: Here's the obligatory link: What Every Computer Scientist Should Know About Floating-Point Arithmetic Basically, there are many base 10 numbers that cannot be exactly represented in the floating point format used by most

Why is OCaml's (+) not polymorphic?

由 你离开我真会死。 提交于 2019-11-28 06:48:28
I am an OCaml newbie. I like OCaml's speed but I don't fully understand its design. For example, I would like the + operator to be polymorphic to support integer, float and so on. Why do we need +. ? Ocaml does not support polymorphic operators (numeric or otherwise) other than comparison operators. The + versus +. thing removes a lot of subtle bugs which can crop up in converting different sizes of integers, floats, and other numeric types back and forth. It also means that the compiler always knows exactly which numeric type is in use, thus making it easier to recognize when the programmer

C# double addition - strange behaviour

由 那年仲夏 提交于 2019-11-28 06:07:21
问题 public static void Main() { Dictionary<string, double> values = new Dictionary<string, double>(); values.Add("a", 0.002); values.Add("b", 0.003); values.Add("c", 0.012); // Summing iteratively. double v1 = 615.0; foreach (KeyValuePair<string, double> kp in values) { v1 += kp.Value; } Console.WriteLine(v1); // Summing using the Sum method. double v2 = 615.0; v2 += values.Values.Sum(); Console.WriteLine(v2); Console.ReadLine(); } When I look at the value of v1 in the debugger it gives a value

Why does adding two decimals in Javascript produce a wrong result? [duplicate]

由 早过忘川 提交于 2019-11-27 17:57:33
Possible Duplicate: Is JavaScript’s Math broken? Why does JS screw up this simple math? console.log(.1 + .2) // 0.3000000000000004 console.log(.3 + .6) // 0.8999999999999999 The first example is greater than the correct result, while the second is less. ???!! How do you fix this? Do you have to always convert decimals into integers before performing operations? Do I only have to worry about adding (* and / don't appear to have the same problem in my tests)? I've looked in a lot of places for answers. Some tutorials (like shopping cart forms) pretend the problem doesn't exist and just add

Are 'addition' and 'bitwise or' the same in this case?

由 房东的猫 提交于 2019-11-27 17:28:01
问题 Say I have four 32-bit numbers, defined so that their bits don't overlap, i.e. unsigned long int num0 = 0xFF000000; unsigned long int num1 = 0x00FF0000; unsigned long int num2 = 0x0000FF00; unsigned long int num3 = 0x000000FF; Where in each number one could have anything in the place of the FF s. Am I right in saying that addition and bitwise or would always produce the same output for such sort of numbers? Thanks! 回答1: as long as for two numbers num1 and num2 applies num1 & num2 == 0 , then

Time calculation in php (add 10 hours)?

由 我是研究僧i 提交于 2019-11-27 13:11:33
I get the time: $today = time(); $date = date('h:i:s A', strtotime($today)); if the current time is "1:00:00 am", how do i add 10 more hours to become 11:00:00 am?? strtotime() gives you a number back that represents a time in seconds. To increment it, add the corresponding number of seconds you want to add. 10 hours = 60*60*10 = 36000, so... $date = date('h:i:s A', strtotime($today)+36000); // $today is today date Edit: I had assumed you had a string time in $today - if you're just using the current time, even simpler: $date = date('h:i:s A', time()+36000); // time() returns a time in seconds

Why is subtraction faster than addition in Python?

由 我怕爱的太早我们不能终老 提交于 2019-11-27 11:31:57
问题 I was optimising some Python code, and tried the following experiment: import time start = time.clock() x = 0 for i in range(10000000): x += 1 end = time.clock() print '+=',end-start start = time.clock() x = 0 for i in range(10000000): x -= -1 end = time.clock() print '-=',end-start The second loop is reliably faster, anywhere from a whisker to 10%, depending on the system I run it on. I've tried varying the order of the loops, number of executions etc, and it still seems to work. Stranger,

How to combine the sequence of objects in jq into one object?

由 余生颓废 提交于 2019-11-27 11:27:53
问题 I would like to convert the stream of objects: { "a": "green", "b": "white" } { "a": "red", "c": "purple" } into one object: { "a": "red", "b": "white", "c": "purple" } Also, how can I wrap the same sequence into an array? [ { "a": "green", "b": "white" }, { "a": "red", "c": "purple" } ] Sadly, the manual is seriously lacking in comprehensiveness, and googling doesn't find the answers either. 回答1: If your input is a stream of objects, then unless your jq has inputs , the objects must be

How to access the carry flag while adding two 64 bit numbers using asm in C

由 ぃ、小莉子 提交于 2019-11-27 08:26:52
问题 Yeah thanks that works. @PeterCordes. Also __int128 works. But one more thing as you said using the intrinsics of multiprecision arithmetic that is _addcarry_u64 in C, using the header file immintrin.h I have the following code #include <stdio.h> #include <stdlib.h> #include <stdint.h> #include <immintrin.h> unsigned char _addcarry_u64(unsigned char c_in, uint64_t src1, uint64_t src2,uint64_t *sum); int main() { unsigned char carry; uint64_t sum; long long int c1=0,c2=0; uint64_t a
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