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基础算法模板――高精度运算
1. 高精度加法
vector<int> add(vector<int> &A, vector<int> &B) { if (A.size() < B.size()) return add(B, A); vector<int> C; int t = 0; for (int i = 0; i < A.size(); i ++ ) { t += A[i]; if (i < B.size()) t += B[i]; C.push_back(t % 10); t /= 10; } if (t) C.push_back(t); return C; }
2. 高精度减法
#include <iostream> #include <vector> using namespace std; bool cmp(vector<int> &A, vector<int> &B) { if (A.size() != B.size()) return A.size() > B.size(); for (int i = A.size() - 1; i >= 0; i -- ) if (A[i] != B[i]) return A[i] > B[i]; return true; } vector<int> sub(vector<int> &A, vector<int> &B) { vector<int> C; for (int i = 0, t = 0; i < A.size(); i ++ ) { t = A[i] - t; if (i < B.size()) t -= B[i]; C.push_back((t + 10) % 10); if (t < 0) t = 1; else t = 0; } while (C.size() > 1 && C.back() == 0) C.pop_back(); return C; } int main() { string a, b; vector<int> A, B; cin >> a >> b; for (int i = a.size() - 1; i >= 0; i -- ) A.push_back(a[i] - '0'); for (int i = b.size() - 1; i >= 0; i -- ) B.push_back(b[i] - '0'); vector<int> C; if (cmp(A, B)) C = sub(A, B); else C = sub(B, A), cout << '-'; for (int i = C.size() - 1; i >= 0; i -- ) cout << C[i]; cout << endl; return 0; }
3. 高精度乘法
#include <iostream> #include <vector> using namespace std; vector<int> mul(vector<int> &A, int b) { vector<int> C; int t = 0; for (int i = 0; i < A.size() || t; i ++ ) { if (i < A.size()) t += A[i] * b; C.push_back(t % 10); t /= 10; } return C; } int main() { string a; int B; vector<int> A; cin >> a >> B; for (int i = a.size() - 1; i >= 0; i -- ) A.push_back(a[i] - '0'); auto C = mul(A, B); for (int i = C.size() - 1; i >= 0; i -- ) cout << C[i]; cout << endl; return 0; }
4. 高精度除法
#include <iostream> #include <vector> #include <algorithm> using namespace std; vector<int> div(vector<int> &A, int b, int &r) { vector<int> C; r = 0; for (int i = A.size() - 1; i >= 0; i -- ) { r = r * 10 + A[i]; C.push_back(r / b); r %= b; } reverse(C.begin(), C.end()); while (C.size() > 1 && C.back() == 0) C.pop_back(); return C; } int main() { string a; vector<int> A; int B; cin >> a >> B; for (int i = a.size() - 1; i >= 0; i -- ) A.push_back(a[i] - '0'); int r; auto C = div(A, B, r); for (int i = C.size() - 1; i >= 0; i -- ) cout << C[i]; cout << endl << r << endl; return 0; }
文章来源: https://blog.csdn.net/qq_40028201/article/details/91338356