问题
I came across below program which looks perfect. Per me its time complexity is nlogn where n is the length of String.
n for storing different strings,nlog for sorting, n for comparison. So time complexity is nlogn. Space complexity is n for storing the storing n substrings
My question is can it be further optimized ?
public class LRS {
// return the longest common prefix of s and t
public static String lcp(String s, String t) {
int n = Math.min(s.length(), t.length());
for (int i = 0; i < n; i++) {
if (s.charAt(i) != t.charAt(i))
return s.substring(0, i);
}
return s.substring(0, n);
}
// return the longest repeated string in s
public static String lrs(String s) {
// form the N suffixes
int n = s.length();
String[] suffixes = new String[n];
for (int i = 0; i < n; i++) {
suffixes[i] = s.substring(i, n);
}
// sort them
Arrays.sort(suffixes);
// find longest repeated substring by comparing adjacent sorted suffixes
String lrs = "";
for (int i = 0; i < n-1; i++) {
String x = lcp(suffixes[i], suffixes[i+1]);
if (x.length() > lrs.length())
lrs = x;
}
return lrs;
}
public static void main(String[] args) {
String s = "MOMOGTGT";
s = s.replaceAll("\\s+", " ");
System.out.println("'" + lrs(s) + "'");
}
}
回答1:
Have a look at this algorithm given in geeksforgeeks, this might be helpful:
http://www.geeksforgeeks.org/suffix-tree-application-3-longest-repeated-substring/
来源:https://stackoverflow.com/questions/40070310/find-longest-repeating-substring-in-string