I am using an IBInspectable Int in Swift to choose between 4 four shapes (0-3), however it is possible in the storyboard editor to set a value greater than 3 and less than 0, which stops the IBDesignable system working.
Is it possible to set a min and max limit of what values can be set in the storyboard editor?
let SHAPE_CROSS = 0
let SHAPE_SQUARE = 1
let SHAPE_CIRCLE = 2
let SHAPE_TRIANGLE = 3
@IBInspectable var shapeType: Int = 0
@IBInspectable var shapeSize: CGFloat = 100.0
@IBInspectable var shapeColor: UIColor?
There's no way to limit what a user can input in Storyboard. However, you could prevent invalid values from being stored using a computed property:
@IBInspectable var shapeType: Int {
set(newValue) {
internalShapeType = min(newValue, 3)
}
get {
return internalShapeType
}
}
var internalShapeType: Int = 0
Then you could also use an enum
instead of constants to represent your different shape types internally.
来源:https://stackoverflow.com/questions/30831609/how-to-set-a-max-limit-for-an-ibinspectable-int