How to get a distinct result with nHibernate and QueryOver API?

问题

I have this Repository method

    public IList<Message> ListMessagesBy(string text, IList<Tag> tags, int pageIndex, out int count, out int pageSize)
    {
        pageSize = 10;
        var likeString = string.Format("%{0}%", text);
        var query = session.QueryOver<Message>()
            .Where(Restrictions.On<Message>(m => m.Text).IsLike(likeString) || 
            Restrictions.On<Message>(m => m.Fullname).IsLike(likeString));

        if (tags.Count > 0)
        {
            var tagIds = tags.Select(t => t.Id).ToList();
            query
                .JoinQueryOver<Tag>(m => m.Tags)
                .WhereRestrictionOn(t => t.Id).IsInG(tagIds);
        }            

        count = 0;
        if(pageIndex < 0)
        {
            count = query.ToRowCountQuery().FutureValue<int>().Value;
            pageIndex = 0;
        }
        return query.OrderBy(m => m.Created).Desc.Skip(pageIndex * pageSize).Take(pageSize).List();
    }

You supply a free text search string and a list of Tags. The problem is that if a message has more then one tag it is listed duplicated times. I want a distinct result based on the Message entity. I've looked at

Projections.Distinct

But it requires a list of Properties to to the distinct question on. This Message is my entity root there most be a way of getting this behaviour without supplying all of the entity properties?

Thanks in advance, Anders

回答1:

If you're using the ICriteria API, you need:

.SetResultTransformer(new DistinctEntityRootTransformer())

If you're using the QueryOver API, you need:

.TransformUsing(Transformers.DistinctRootEntity)

But beware, this all occurs on client side, so all the duplicate rows are still pulled.

回答2:

Try something like this

public IPagedList<Client> Find(int pageIndex, int pageSize)
{
    Client clientAlias = null;

    var query = Session.QueryOver<Client>(() => clientAlias)

        .Select(
            Projections.Distinct(
                Projections.ProjectionList()
                    .Add(Projections.Property<Client>(x => x.Id).As("Id"))
                    .Add(Projections.Property<Client>(x => x.Name).As("Name"))
                    .Add(Projections.Property<Client>(x => x.Surname).As("Surname"))
                    .Add(Projections.Property<Client>(x => x.GivenName).As("GivenName"))
                    .Add(Projections.Property<Client>(x => x.EmailAddress).As("EmailAddress"))
                    .Add(Projections.Property<Client>(x => x.MobilePhone).As("MobilePhone"))
            )
        )
        .TransformUsing(Transformers.AliasToBean<Client>())

        .OrderBy(() => clientAlias.Surname).Asc
        .ThenBy(() => clientAlias.GivenName).Asc;

    var count = query
        .ToRowCountQuery()
        .FutureValue<int>();

    return query
        .Take(pageSize)
        .Skip(Pagination.FirstResult(pageIndex, pageSize))
        .List<Client>()
        .ToPagedList(pageIndex, pageSize, count.Value);
}

回答3:

You can use SelectList and GroupBy, e.g:

tags.SelectList(t => t.SelectGroup(x => x.Id))

Should work and produce the same query plan as distinct.

If you need multiple items in the group, do something like:

tags.SelectList(t => t.SelectGroup(x => x.Id)
                      .SelectGroup(x => x.Name)
               )

回答4:

I have recently created a method to apply select distinct based on a mapped object type. It applies this to an IQueryOver object (property of class). Method also has access to the nhibernate config. You could add these as method parameters. Needs work for production, but method is working great in dev, only used it for one entity so far.

This method was created because I am trying to page my data at the server level and a distinct result transformer would not work.

After you get your object collection (query.List()) you may have to reload the objects to populate one to many child objects. Many to one mappings will be proxied for lazy loads.

 public void DistinctRootProjectionList<E>()
    {
        var classMapping = Context.Config.GetClassMapping(typeof(E));
        var propertyIterator = classMapping.UnjoinedPropertyIterator;
        List<IProjection> projections = new List<IProjection>();
        ProjectionList list = Projections.ProjectionList();

        list.Add(Projections.Property(classMapping.IdentifierProperty.Name), classMapping.IdentifierProperty.Name);

        foreach (var item in propertyIterator)
        {
            if (item.Value.IsSimpleValue || item.Value.Type.IsEntityType)
            {
                list.Add(Projections.Property(item.Name), item.Name);
            }
        }
        query.UnderlyingCriteria.SetProjection(Projections.Distinct(list));
        query.TransformUsing(Transformers.AliasToBean<E>());
    }

Code I used to load one to many relations... T is the entity type.

for (int i = 0; i < resp.Data.Count; i++)
        {
            resp.Data[i] = session.Load<T>(GetInstanceIdValue(resp.Data[i]));
        }

来源：https://stackoverflow.com/questions/4615675/how-to-get-a-distinct-result-with-nhibernate-and-queryover-api

标签

nhibernate

queryover