Golang: Implementing a cron / executing tasks at a specific time

Question

I have been looking around for examples on how to implement a function that allows you to execute tasks at a certain time in Go, but I couldn't find anything.

I implemented one myself and I am sharing it in the answers, so other people can have a reference for their own implementation.

Answer 1

This is a general implementation, which lets you set:

• interval period
• hour to tick
• minute to tick
• second to tick

UPDATED: (the memory leak was fixed)

import (
"fmt"
"time"
)

const INTERVAL_PERIOD time.Duration = 24 * time.Hour

const HOUR_TO_TICK int = 23
const MINUTE_TO_TICK int = 00
const SECOND_TO_TICK int = 03

type jobTicker struct {
    timer *time.Timer
}

func runningRoutine() {
    jobTicker := &jobTicker{}
    jobTicker.updateTimer()
    for {
        <-jobTicker.timer.C
        fmt.Println(time.Now(), "- just ticked")
        jobTicker.updateTimer()
    }
}

func (t *jobTicker) updateTimer() {
    nextTick := time.Date(time.Now().Year(), time.Now().Month(), 
    time.Now().Day(), HOUR_TO_TICK, MINUTE_TO_TICK, SECOND_TO_TICK, 0, time.Local)
    if !nextTick.After(time.Now()) {
        nextTick = nextTick.Add(INTERVAL_PERIOD)
    }
    fmt.Println(nextTick, "- next tick")
    diff := nextTick.Sub(time.Now())
    if t.timer == nil {
        t.timer = time.NewTimer(diff)
    } else {
        t.timer.Reset(diff)
    }
}

Answer 2

the answer provided by @Daniele B is not good enough, as @Caleb says, that implementation leaks memory, because each time we create a new ticker, the old one will never be released.

so I wrap the time.timer, and reset it everytime, a example here:

package main

import (
    "fmt"
    "time"
)

const INTERVAL_PERIOD time.Duration = 24 * time.Hour

const HOUR_TO_TICK int = 23
const MINUTE_TO_TICK int = 21
const SECOND_TO_TICK int = 03

type jobTicker struct {
    t *time.Timer
}

func getNextTickDuration() time.Duration {
    now := time.Now()
    nextTick := time.Date(now.Year(), now.Month(), now.Day(), HOUR_TO_TICK, MINUTE_TO_TICK, SECOND_TO_TICK, 0, time.Local)
    if nextTick.Before(now) {
        nextTick = nextTick.Add(INTERVAL_PERIOD)
    }
    return nextTick.Sub(time.Now())
}

func NewJobTicker() jobTicker {
    fmt.Println("new tick here")
    return jobTicker{time.NewTimer(getNextTickDuration())}
}

func (jt jobTicker) updateJobTicker() {
    fmt.Println("next tick here")
    jt.t.Reset(getNextTickDuration())
}

func main() {
    jt := NewJobTicker()
    for {
        <-jt.t.C
        fmt.Println(time.Now(), "- just ticked")
        jt.updateJobTicker()
    }
}

Answer 3

In case someone drops in on this question searching for a quick solution. I found a neat library that makes it really easy to schedule jobs.

Link: https://github.com/jasonlvhit/gocron

The API is pretty straightforward:

import (
    "fmt"
    "github.com/jasonlvhit/gocron"
)

func task() {
    fmt.Println("Task is being performed.")
}

func main() {
    s := gocron.NewScheduler()
    s.Every(2).Hours().Do(task)
    <- s.Start()
}

Answer 4

I have created a package that actually supports crontab syntax if you are familiar with it, for example:

ctab := crontab.New()
ctab.AddJob("*/5 * * * *", myFunc)
ctab.AddJob("0 0 * * *", myFunc2)

Package link: https://github.com/mileusna/crontab

Answer 5

This is another general implementation. No need for a third party library.

Run a func once a day at noon.

• Period: time.Hour * 24
• Offset: time.Hour * 12

Run a func twice a day at 03:40 and 16:40.

• Period: time.Hour * 12
• Offset: time.Hour * 3 + time.Minute * 40;

package main

import (
    "fmt"
    "time"
)

// Repeat calls function `f` with a period `d` offsetted by `o`.
func Repeat(d time.Duration, o time.Duration, f func(time.Time)) {
    next := time.Now().Truncate(d).Add(o)
    if next.Before(time.Now()) {
        next = next.Add(d)
    }

    t := time.NewTimer(next.Sub(time.Now()))

    for {
        v := <-t.C
        next = next.Add(d)
        t.Reset(next.Sub(time.Now()))
        f(v)
    }
}