SQL进阶系列之5外连接的用法

独自空忆成欢 提交于 2019-11-30 01:36:46

写在前面

SQL本身是作为一种数据提取工具而出现,使用SQL生成各种定制化报表和非定制化报表并非SQL原本用途的功能,但这并不意味着SQL无法实现这些功能。

用外连接进行行列转换(1)(行 → 列):制作交叉表

-- 建表语句
/* 用外连接进行行列转换(1)(行→列):制作交叉表 */
CREATE TABLE Courses
(name   VARCHAR(32), 
 course VARCHAR(32), 
 PRIMARY KEY(name, course));

INSERT INTO Courses VALUES('赤井', 'SQL入门');
INSERT INTO Courses VALUES('赤井', 'UNIX基础');
INSERT INTO Courses VALUES('铃木', 'SQL入门');
INSERT INTO Courses VALUES('工藤', 'SQL入门');
INSERT INTO Courses VALUES('工藤', 'Java中级');
INSERT INTO Courses VALUES('吉田', 'UNIX基础');
INSERT INTO Courses VALUES('渡边', 'SQL入门');
-- 水平展开求交叉表(1):使用外连接
SELECT C0.name,
CASE WHEN C1.name IS NOT NULL THEN '○' ELSE NULL END AS “SQL入门",
CASE WHEN C2.name IS NOT NULL THEN '○' ELSE NULL END AS "UNIX基础",
CASE WHEN C3.name IS NOT NULL THEN '○' ELSE NULL END AS "Java中级"
FROM (SELECT DISTINCT name FROM Courses) AS C0
LEFT JOIN (SELECT name FROM Courses WHERE course = 'SQL入门') AS C1 ON C0.name = C1.name
LEFT JOIN (SELECT name FROM Courses WHERE course = 'UNIX基础') AS C2 ON C0.name = C2.name
LEFT JOIN (SELECT name FROM Courses WHERE course = 'Java中级') AS C3 ON C0.name = C3.name;
-- 评价:方法直观并容易理解,但大量用到内嵌视图和连接操作,随着列数增加,代码会臃肿,性能也会恶化
-- 水平展开求交叉表(2):使用标量子查询
SELECT C0.name,
(SELECT '○' FROM Courses AS C1 WHERE course = 'SQL入门' AND C1.name = C0.name) AS "SQL入门",
(SELECT '○' FROM Courses AS C2 WHERE course = 'UNIX基础' AND C2.name = C0.name) AS "UNIX基础",
(SELECT '○' FROM Courses AS C3 WHERE course = 'Java中级' AND C3.name = C0.name) AS "Java中级"
FROM (SELECT DISTINCT name FROM Courses) AS C0;
-- 在增加课程时,只需要修改SELECT子句后面的内容,代码修改比较简单,应对需求变更比较理想,缺点是性能不好,在SELECT子句中使用标量子查询和关联子查询时,计算开销较大
-- 水平展开求交叉表(3):嵌套使用CASE WHEN表达式
SELECT name,
CASE WHEN SUM(CASE WHEN course = 'SQL入门' THEN 1 ELSE 0 END) = 1 THEN '○' ELSE NULL END AS "SQL入门",
CASE WHEN SUM(CASE WHEN course = 'UNIX基础' THEN 1 ELSE 0 END) = 1 THEN '○' ELSE NULL END AS "UNIX基础",
CASE WHEN SUM(CASE WHEN course = 'Java中级' THEN 1 ELSE 0 END) = 1 THEN '○' ELSE NULL END AS "Java中级"
FROM Courses
GROUP BY name;

用外连接进行行列转换(2)(列 → 行):汇总重复项于一列

-- 建表语句
/* 用外连接进行行列转换(2)(列→行):汇总重复项于一列 */
CREATE TABLE Personnel
 (employee   varchar(32), 
  child_1    varchar(32), 
  child_2    varchar(32), 
  child_3    varchar(32), 
  PRIMARY KEY(employee));

INSERT INTO Personnel VALUES('赤井', '一郎', '二郎', '三郎');
INSERT INTO Personnel VALUES('工藤', '春子', '夏子', NULL);
INSERT INTO Personnel VALUES('铃木', '夏子', NULL,   NULL);
INSERT INTO Personnel VALUES('吉田', NULL,   NULL,   NULL);
-- 列数据转行数据(不去除空行)
SELECT employee,child_1 FROM Personnel
UNION ALL
SELECT employee,child_2 FROM Personnel
UNION ALL
SELECT employee,child_3 FROM Personnel;
-- 列数据转行数据(去除空行)
SELECT employee,child_1 FROM Personnel WHERE child_1 IS NOT NULL
UNION ALL
SELECT employee,child_2 FROM Personnel WHERE child_2 IS NOT NULL
UNION ALL
SELECT employee,child_3 FROM Personnel WHERE child_3 IS NOT NULL;
-- 按需自定义保留记录(不完全去除重复行)

-- 准备所有孩子的视图
CREATE VIEW Children(child) AS 
SELECT child_1 FROM Personnel
UNION SELECT child_2 FROM Personnel
UNION SELECT child_3 FROM Personnel;

-- 获取员工子女列表的SQL语句(没有孩子的员工也要输出)
SELECT Personnel.employee,Children.child
FROM Personnel 
LEFT JOIN Children 
ON Children.child IN (Personnel.child_1,Personnel.child_2,Personnel.child_3);

在交叉表里制作嵌套式表侧栏

/* 在交叉表里制作嵌套式表侧栏 */
CREATE TABLE TblSex
(sex_cd   char(1), 
 sex varchar(5), 
 PRIMARY KEY(sex_cd));

CREATE TABLE TblAge 
(age_class char(1), 
 age_range varchar(30), 
 PRIMARY KEY(age_class));

CREATE TABLE TblPop 
(pref_name  varchar(30), 
 age_class  char(1), 
 sex_cd     char(1), 
 population integer, 
 PRIMARY KEY(pref_name, age_class,sex_cd));

INSERT INTO TblSex (sex_cd, sex ) VALUES('m',   '男');
INSERT INTO TblSex (sex_cd, sex ) VALUES('f',   '女');

INSERT INTO TblAge (age_class, age_range ) VALUES('1',  '21岁~30岁');
INSERT INTO TblAge (age_class, age_range ) VALUES('2',  '31岁~40岁');
INSERT INTO TblAge (age_class, age_range ) VALUES('3',  '41岁~50岁');

INSERT INTO TblPop VALUES('秋田', '1', 'm', 400 );
INSERT INTO TblPop VALUES('秋田', '3', 'm', 1000 );
INSERT INTO TblPop VALUES('秋田', '1', 'f', 800 );
INSERT INTO TblPop VALUES('秋田', '3', 'f', 1000 );
INSERT INTO TblPop VALUES('青森', '1', 'm', 700 );
INSERT INTO TblPop VALUES('青森', '1', 'f', 500 );
INSERT INTO TblPop VALUES('青森', '3', 'f', 800 );
INSERT INTO TblPop VALUES('东京', '1', 'm', 900 );
INSERT INTO TblPop VALUES('东京', '1', 'f', 1500 );
INSERT INTO TblPop VALUES('东京', '3', 'f', 1200 );
INSERT INTO TblPop VALUES('千叶', '1', 'm', 900 );
INSERT INTO TblPop VALUES('千叶', '1', 'f', 1000 );
INSERT INTO TblPop VALUES('千叶', '3', 'f', 900 );
-- 构造侧边栏
SELECT age_class,age_range,sex_cd,sex 
FROM TblAge CROSS JOIN TblSex;
-- 处理TblPop表
SELECT age_class,sex_cd,
SUM(CASE WHEN pref_name IN ('秋田','青森') THEN population ELSE 0 END) AS "东北",
SUM(CASE WHEN pref_name IN ('东京','千叶') THEN population ELSE 0 END) AS "关东"
FROM TblPop
GROUP BY age_class,sex_cd;
-- 连接两张表
SELECT A.age_range,A.sex,B.东北,B.关东 
FROM (SELECT age_class,age_range,sex_cd,sex FROM TblAge CROSS JOIN TblSex) AS A 
LEFT JOIN (SELECT age_class,sex_cd,
SUM(CASE WHEN pref_name IN ('秋田','青森') THEN population ELSE 0 END) AS "东北",
SUM(CASE WHEN pref_name IN ('东京','千叶') THEN population ELSE 0 END) AS "关东"
FROM TblPop
GROUP BY age_class,sex_cd) AS B
ON A.age_class = B.age_class and A.sex_cd = B.sex_cd;

作为乘法运算的连接

-- 建表语句
/* 作为乘法运算的连接 */
CREATE TABLE Items
 (item_no INTEGER PRIMARY KEY,
  item    VARCHAR(32) NOT NULL);

INSERT INTO Items VALUES(10, 'FD');
INSERT INTO Items VALUES(20, 'CD-R');
INSERT INTO Items VALUES(30, 'MO');
INSERT INTO Items VALUES(40, 'DVD');

CREATE TABLE SalesHistory
 (sale_date DATE NOT NULL,
  item_no   INTEGER NOT NULL,
  quantity  INTEGER NOT NULL,
  PRIMARY KEY(sale_date, item_no));

INSERT INTO SalesHistory VALUES('2007-10-01',  10,  4);
INSERT INTO SalesHistory VALUES('2007-10-01',  20, 10);
INSERT INTO SalesHistory VALUES('2007-10-01',  30,  3);
INSERT INTO SalesHistory VALUES('2007-10-03',  10, 32);
INSERT INTO SalesHistory VALUES('2007-10-03',  30, 12);
INSERT INTO SalesHistory VALUES('2007-10-04',  20, 22);
INSERT INTO SalesHistory VALUES('2007-10-04',  30,  7);
-- 要求得到所有item即便没有销售记录的quantity求和
-- 方法一:连接前聚合,然后一对一进行连接
SELECT Items.item_no,SH.quantity
FROM Items LEFT JOIN (
SELECT item_no,sum(quantity) as quantity
FROM SalesHistory
GROUP BY item_no) AS SH
ON Items.item_no = SH.item_no;
-- 评价:从性能角度讲,通过聚合将SH上的item_no变成了非空不重复,但SH本身不存在主键索引,无法利用查询优化
-- 方法二:一对多进行连接不会增加行
SELECT Items.item_no,sum(SH.quantity) AS quantity
FROM Items 
LEFT JOIN SalesHistory AS SH
ON Items.item_no = SH.item_no
GROUP BY Items.item_no;
-- 评价:这种方法没有使用临时视图,性能会有所改善

全外连接

面向集合的角度理解连接类型

  • 左外连接 LEFT OUTER JOIN
  • 右外连接 RIGHT OUTER JOIN
  • 全外连接 FULL OUTER JOIN
/* 全外连接 */
CREATE TABLE Class_A
(id char(1), 
 name varchar(30), 
 PRIMARY KEY(id));

CREATE TABLE Class_B
(id   char(1), 
 name varchar(30), 
 PRIMARY KEY(id));

INSERT INTO Class_A (id, name) VALUES('1', '田中');
INSERT INTO Class_A (id, name) VALUES('2', '铃木');
INSERT INTO Class_A (id, name) VALUES('3', '伊集院');

INSERT INTO Class_B (id, name) VALUES('1', '田中');
INSERT INTO Class_B (id, name) VALUES('2', '铃木');
INSERT INTO Class_B (id, name) VALUES('4', '西园寺');
-- 全外连接保留全部信息
SELECT 
COALESCE(A.id,B.id) AS id,A.name AS a_name,B.name AS b_name
FROM Class_A AS a FULL JOIN Class_B AS b
ON A.id = B.id;

-- 数据库不支持全外连接时的替代方案
SELECT A.id AS id,A.name,B.name FROM Class_A AS A LEFT JOIN Class_B AS B ON A.id = B.id
UNION
SELECT B.id AS id,A.name,B.name FROM Class_A AS A RIGHT JOIN Class_B AS B ON A.id = B.id;

INNER JOIN(或者INTERSECT)相当于交集,UNION(LEFT JOIN AND RIGHT JOIN ,再或者FULL JOIN)相当于并集

用外连接进行集合运算

用外连接求差集:A-B

SELECT A.id,A.name AS A_name,B.name AS B_name FROM Class_A AS A LEFT JOIN Class_B AS B ON A.id = B.id WHERE B.name IS NULL;

用外连接求差集:B-A

SELECT A.id,A.name AS A_name,B.name AS B_name FROM Class_A AS A RIGHT JOIN Class_B AS B ON A.id = B.id WHERE A.name IS NULL;

用全外连接求异或集

SELECT COALESCE(A.id,B.id) AS id,COALESCE(A.name,B.name) AS name FROM Class_A AS A FULL JOIN Class_B AS B ON A.id = B.id WHERE A.name IS NULL OR B.name IS NULL;

本节小结

  • SQL不是用来生成报表的语言,不建议用齐进行格式转换
  • 必要时可以考虑外连接和CASE表达式来解决问题
  • 生成嵌套表侧栏时,如果先生成主表的笛卡尔积再进行连接,很容易就可以完成
  • 从行数来看,表连接可以看成乘法。因此,当表之间是一对多的关系时,连接后行数不会增加
  • 外连接的思想和集合运算很像,使用外连接可以实现各种集合运算

练习题

-- 练习题 1-5-1 :先连接还是先聚合
SELECT master.age_range,master.sex,
SUM(CASE WHEN data.pref_name IN ('青森','秋田') THEN population ELSE NULL END) AS "东北",
SUM(CASE WHEN data.pref_name IN ('东京','千叶') THEN population ELSE NULL END) AS "关东"
FROM (TblAge CROSS JOIN TblSex) AS master 
LEFT JOIN TblPop AS data 
ON master.age_class = data.age_class
AND master.sex_cd = data.sex_cd
GROUP BY master.age_range,master.sex;
-- 练习题 1-5-2:请留意孩子的人数
SELECT Personnel.employee,COUNT(Children.child)
FROM Personnel 
LEFT JOIN Children 
ON Children.child IN (Personnel.child_1,Personnel.child_2,Personnel.child_3)
GROUP BY Personnel.employee;
-- 练习题 1-5-3 全外连接和merge运算符
MERGE INTO Class_A A
    USING (SELECT *
             FROM Class_B ) B
      ON (A.id = B.id)
    WHEN MATCHED THEN
        UPDATE SET A.name = B.name
    WHEN NOT MATCHED THEN
        INSERT (id, name) VALUES (B.id, B.name);
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