Generate PCR from PTS

↘锁芯ラ 提交于 2019-11-28 20:55:17

First, the PCR has 33+9 bits, the PTS 33 bits. The 33 bit-portion (called PCR_base) runs at 90kHz, as does the PTS. The remaining 9 bits are called PCR_ext and run at 27MHz.

Thus, this is how you could calculate the PCR:

S64 nPcr = (S64)nPts << 9;

Note that there should be a time-offset between the PTSs of the multiplexed streams and the PCR, it's usually in the range of a few hundred ms, depending on the stream.

The respective decoder needs some time to decode the data and get it ready for presentation at the time given by the respective PTS, that's why the PTSs are always "ahead" of the PCR. ISO-13818 and some DVB specs give specifics about buffering and (de)multiplexing.

About your bitshifting I'm not sure, this is a code snippet of mine. The comment may help in shifting the bits to the right place, R stands for reserved.

data[4] = 7;
data[5] = 1 << 4;   // PCR_flag

// pcr has 33+9=42 bits

//        4           3          2          1          0
// 76543210 98765432 10987654 32109876 54321098 76543210
// xxxxxxxx xxxxxxxx xxxxxxxx xxxxxxxx xRRRRRRx xxxxxxxx
// 10987654 32109876 54321098 76543210 9      8 76543210
//  4          3          2          1                 0
// b6       b7       b8       b9       b10      b11

data[ 6] = (pcr >> 34) & 0xff;
data[ 7] = (pcr >> 26) & 0xff;
data[ 8] = (pcr >> 18) & 0xff;
data[ 9] = (pcr >> 10) & 0xff;
data[10] = 0x7e | ((pcr & (1 << 9)) >> 2) | ((pcr & (1 << 8)) >> 8);
data[11] = pcr & 0xff;

The answer of @schieferstapel is correct. I am only adding one more note here which refers to an exception.

There are times when B frames arrives after (who's PTS is less than) P frames. so PTS can be non-linear if every picture is stamped with PTS value. Whereas, PCR must be incrementally linear.

So in the above situation, you must try to either omit B frames or make relevant calculation when putting PCR values. Also, if this is hardware playouts, it is advisable that PCR should be slightly ahead (lesser by 400 ms or so) than PTS of corresponding I frames.

the PCR contains 33(PCR_Base)+6(PCR_const)+9(PCR_Ext) number of bits and also it states that the first 33 bits are based on a 90 kHz clock while the last 9 are based on a 27 MHz clock.PCR_const = 0x3F PCR_Ext=0 PCR_Base=pts/dts

Below code is easy understand.

    PCR_Ext = 0;
    PCR_Const = 0x3F;
    int64_t pcrv = PCR_Ext & 0x1ff;
    pcrv |= (PCR_Const << 9) & 0x7E00;
    pcrv |= (PCR_Base << 15) & 0xFFFFFFFF8000LL;

    pp = (char*)&pcrv;
    data[ 6] = pp[5];
    data[ 7] = pp[4];
    data[ 8] = pp[3];
    data[ 9] = pp[2];
    data[10] = pp[1];
    data[11] = pp[0];
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