I need to parse date and time. Here is what I've got:
import time
a = time.strptime('Apr 28 2013 23:01', "%b %d %y %H:%M")
print a
But it gives me
Traceback (most recent call last):
File "/home/aaa/Documents/python_test.py", line 17, in <module>
a = time.strptime('Apr 28 2013 23:01', "%b %d %y %H:%M")
File "/usr/lib/python2.7/_strptime.py", line 467, in _strptime_time
return _strptime(data_string, format)[0]
File "/usr/lib/python2.7/_strptime.py", line 325, in _strptime
(data_string, format))
ValueError: time data 'Apr 28 2013 23:01' does not match format '%b %d %y %H:%M'
What am I doing wrong?
%y
should be %Y
for a 4 digit year...
From the docs:
%y Year without century as a decimal number [00,99].
%Y Year with century as a decimal number.
You can
import time
a = time.strptime('Apr 28 2013 23:01', "%b %d %Y %H:%M")
print time.strftime("%d/%m/%Y",a)
with Y
. It is followed by a conversion line of code, and gives result
28/04/2013
Jon's answer is of course correct, but as you noticed these things can be difficult to find.
As a general suggestion for debugging strptime
problems I recommend printing out a known datetime
using the format string you use for parsing:
from datetime import datetime
d = datetime(2013, 4, 28, 23, 1)
print d.strftime("%b %d %y %H:%M")
print 'Apr 28 2013 23:01'
A visual comparison of the output lines:
Apr 28 13 23:01
Apr 28 2013 23:01
quickly finds the problem and also works when your format string is correct, but you are working with a different locale (e.g. in Spanish where it would expect 'Abr' instead of 'Apr')
来源:https://stackoverflow.com/questions/16355437/cannot-parse-the-date-in-python