问题
I am trying to get into Java 8 and get my head around streams and lambdas to solve various problems and got stuck on this specific one which I normally use a forEach and store the values in a Map to solve.
How would you write the code to get the expected list using the new features in Java 8 ?
List<Integer> voterA = Arrays.asList(1,2,3,4,5);
List<Integer> voterB = Arrays.asList(1,2,3,4,5);
List<List<Integer>> votes = Arrays.asList(voterA, voterB);
// expected list = (2,4,6,8,10)
List<Integer> sumVotes = ...
回答1:
That one isn't really doable the way you're hoping. The closest you could get would probably be
IntStream.range(0, voterA.size())
.mapToObj(i -> voterA.get(i) + voterB.get(i))
.collect(toList());
...but there's no "zip" operation on streams, largely because two different streams can have backing spliterators that split at different points, so you can't line them up properly.
回答2:
JDK doesn't provide the 'zip' API. But it can be done with third library AbacusUtil:
List<Integer> voterA = Arrays.asList(1, 2, 3, 4, 5);
List<Integer> voterB = Arrays.asList(1, 2, 3, 4, 5);
List<Integer> sumVotes = Stream.zip(voterA, voterB, (a, b) -> a + b).toList();
Disclosure: I'm the developer of AbacusUtil.
来源:https://stackoverflow.com/questions/28592529/java-8-streams-adding-values-from-two-or-more-lists