问题
I have a nested list of strings which I would like to extract them the date. The date format is:
Two numbers (from
01
to12
) hyphen tree letters (a valid month) hyphen two numbers, for example:08-Jan—07
or03-Oct—01
I tried to use the following regex:
r'\d{2}(—|-)(?:Jan|Feb|Mar|Apr|May|Jun|Jul|Aug|Sep|Oct|Nov|Dec)-\d{2,4}'
Then I tested it as follows:
import pandas as pd
df = pd.DataFrame({'blobs':['6-Feb- 1 4 Facebook’s virtual-reality division created a 3-EBÚ7 11 network of 500 free demo stations in Best Buy stores to give people a taste of VR using the Oculus Rift 90 GT 48 headset. But according to a Wednesday report from Business Insider, about 200 of the demo stations will close after low interest from consumers. 17-Feb-2014',
'I think in a store environment getting people to sit down and go through that experience of getting a headset on and getting set up is quite a difficult thing to achieve,” said Geoff Blaber, a CCS Insight analyst. 29—Oct-2012 Blaber 32 FAX 2978 expects that it will get easier when companies can convince 18-Oct-12 credit cards. '
]})
df
Then:
df['blobs'].str.extractall(r'\d{2}(—|-)(?:Jan|Feb|Mar|Apr|May|Jun|Jul|Aug|Sep|Oct|Nov|Dec)-\d{2,4}')
Nevertheless, they are not working. The previous regex doesn't give me anything (i.e. just hypens -
):
Col
0 NaN
1 -
2 -
3 NaN
4 NaN
5 -
...
n -
How can I fix them in order to get?:
Col
0 6-Feb-14, 17-Feb-2014
1 29—Oct-2012, 18-Oct-12
UPDATE
I also tried to:
import re
df['col'] = df.blobs.apply(lambda x: re.findall('\d{2}(—|-)(?:Jan|Feb|Mar|Apr|May|Jun|Jul|Aug|Sep|Oct|Nov|Dec)-\d{2,4}',x))
s = df.apply(lambda x: pd.Series(x['col']),axis=1).stack().reset_index(level=1, drop=True)
s.name = "col"
df = df.drop('col')
df
Nevertheless I also got:
ValueError Traceback (most recent call last)
<ipython-input-4-5e9a34bd159f> in <module>()
3 s = df.apply(lambda x: pd.Series(x['col']),axis=1).stack().reset_index(level=1, drop=True)
4 s.name = "col"
----> 5 df = df.drop('col')
6 df
/usr/local/lib/python3.5/site-packages/pandas/core/generic.py in drop(self, labels, axis, level, inplace, errors)
1905 new_axis = axis.drop(labels, level=level, errors=errors)
1906 else:
-> 1907 new_axis = axis.drop(labels, errors=errors)
1908 dropped = self.reindex(**{axis_name: new_axis})
1909 try:
/usr/local/lib/python3.5/site-packages/pandas/indexes/base.py in drop(self, labels, errors)
3260 if errors != 'ignore':
3261 raise ValueError('labels %s not contained in axis' %
-> 3262 labels[mask])
3263 indexer = indexer[~mask]
3264 return self.delete(indexer)
ValueError: labels ['col'] not contained in axis
回答1:
When you use Series.str.extract or Series.str.extractall, the captured substrings are returned, not the whole matches. So, you need to make sure you capture (i.e. add (
and )
around) the part of pattern you need to grab.
Now, several expected matches in your rows make it more difficult to do with extractall
, it seems you may use Series.str.findall that may return the whole matches if no capturing group is defined in the pattern.
Use
rx = r'\b\d{1,2}[-–—](?:Jan|Feb|Mar|Apr|May|Jun|Jul|Aug|Sep|Oct|Nov|Dec)[-–—](?:\d{4}|\d{2})\b'
df['Col'] = df['blobs'].str.findall(rx).apply(','.join)
The .apply(','.join)
will convert lists to comma-separated strings in Col
column.
The pattern means:
\b
- a word boundary\d{1,2}
- 1 or 2 digits[-–—]
- a hyphen, em- or en-dash(?:Jan|Feb|Mar|Apr|May|Jun|Jul|Aug|Sep|Oct|Nov|Dec)
- any of the 12 month shortened names[-–—]
- a hyphen, em- or en-dash(?:\d{4}|\d{2})
- 4 or 2 digits\b
- a word boundary
来源:https://stackoverflow.com/questions/42254384/pandas-extractall-is-not-extracting-all-cases-given-a-regex