How can I access tablet pen data via Python?

青春壹個敷衍的年華 提交于 2021-02-18 18:26:34

问题


I need to access a windows tablet pen data (such as the surface) via Python. I mainly need the position, pressure, and tilt values.

I know how to access the Wacom pen data but the windows pen is different.

There is a Python library named Kivy that can handle multi-touch but it recognizes my pen as a finger (WM_TOUCH) and not as a pen (WM_PEN).

This is my Kivy code (that doesnt report pressure and tilt):

 from kivy.app import App
 from kivy.uix.widget import Widget

class TouchInput(Widget):

def on_touch_down(self, touch):
    print(touch)
def on_touch_move(self, touch):
    print(touch)
def on_touch_up(self, touch):
    print("RELEASED!",touch)

class SimpleKivy4(App):

def build(self):
    return TouchInput()

There is a wonderful processing library named Tablet that only works with the Wacom tablet with a simple API (e.g., tablet.getPressure())

I need something like this.


回答1:


This solution works for me, adapted to Python 3 from here.

What works: pen, eraser, pen buttons, both pressure sensors.

Install pyglet library first: pip install pyglet. Then use code:

import pyglet

window = pyglet.window.Window()
tablets = pyglet.input.get_tablets()
canvases = []

if tablets:
    print('Tablets:')
    for i, tablet in enumerate(tablets):
        print('  (%d) %s' % (i + 1, tablet.name))
    print('Press number key to open corresponding tablet device.')
else:
    print('No tablets found.')

@window.event
def on_text(text):
    try:
        index = int(text) - 1
    except ValueError:
        return

    if not (0 <= index < len(tablets)):
        return

    name = tablets[i].name

    try:
        canvas = tablets[i].open(window)
    except pyglet.input.DeviceException:
        print('Failed to open tablet %d on window' % index)

    print('Opened %s' % name)

    @canvas.event
    def on_enter(cursor):
        print('%s: on_enter(%r)' % (name, cursor))

    @canvas.event
    def on_leave(cursor):
        print('%s: on_leave(%r)' % (name, cursor))

    @canvas.event
    def on_motion(cursor, x, y, pressure, a, b):  # if you know what "a" and "b" are tell me (tilt?)
        print('%s: on_motion(%r, x=%r, y=%r, pressure=%r, %s, %s)' % (name, cursor, x, y, pressure, a, b))

@window.event
def on_mouse_press(x, y, button, modifiers):
    print('on_mouse_press(%r, %r, %r, %r' % (x, y, button, modifiers))

@window.event
def on_mouse_release(x, y, button, modifiers):
    print('on_mouse_release(%r, %r, %r, %r' % (x, y, button, modifiers))

pyglet.app.run()


来源:https://stackoverflow.com/questions/54003194/how-can-i-access-tablet-pen-data-via-python

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