java.time.format.DateTimeParseException: Text 'Tue Jan 08 00:00:00 IST 2019' could not be parsed at index 0 [duplicate]

问题

This question already has answers here:

java DateTimeFormatterBuilder fails on testtime (2 answers)

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Java - Unparseable date (3 answers)

Closed 2 years ago.

I am facing DateTimeParseException even after giving appropriate format

DateTimeFormatter ft = DateTimeFormatter.ofPattern("EEE MMM dd HH:mm:ss z yyyy");
LocalDateTime.parse("Tue Jan 08 00:00:00 IST 2019", ft);

Please help if I am missing anything?

回答1:

This is probably due to the locale setting on your computer. You might provide a Locale when creating the DateTimeFormatter.

DateTimeFormatter ft = DateTimeFormatter.ofPattern("EEE MMM dd HH:mm:ss z yyyy", Locale.US);

This will ensure that the date is always parsed right.

回答2:

This could be caused by your system locale not using Mon-Sun for week day short names, e.g. same exception will be thrown for German locale:

Locale.setDefault(Locale.GERMAN);
DateTimeFormatter ft = DateTimeFormatter.ofPattern("EEE MMM dd HH:mm:ss z yyyy");
LocalDateTime.parse("Tue Jan 08 00:00:00 IST 2019", ft);

The code will work if you use the matching locale e.g. US:

Locale.setDefault(Locale.US);
DateTimeFormatter ft = DateTimeFormatter.ofPattern("EEE MMM dd HH:mm:ss z yyyy");
LocalDateTime.parse("Tue Jan 08 00:00:00 IST 2019", ft);

来源：https://stackoverflow.com/questions/54095470/java-time-format-datetimeparseexception-text-tue-jan-08-000000-ist-2019-cou