How to get N random integer numbers whose sum is equal to M

问题

I want to make a list of N random INTEGER numbers whose sum is equal to M number.

I have used numpy and dirichlet function in Python, but this generate double random number array, I would like to generate integer random number.

import numpy as np 
np.random.dirichlet(np.ones(n))*m

The solution can use other distribution the sense is resolve the problem.

回答1:

The problem with using dirichlet for this is that it is a distribution over real numbers. It will yield a vector of numbers in the range (0,1), which sum to 1, but truncating or rounding them may remove the guarantee of a specific sum. Following this post we can get the desired effect from the multinomial distribution (using np.random.multinomial), as follows:

from numpy.random import multinomial

np.random.multinomial(m, np.ones(n)/n)

This will generate n integers between 0 and m, whose sum is m, with equal probability of drawing a given position. The easiest way to visualize this is to consider the result as describing a set of draws from a fixed set of objects (e.g., die rolls drawing from the integers from 1 to 6) where the final array is the number of times the corresponding object was drawn. The total will always sum to the given number of total draws (rolls).

回答2:

note that a Dirichlet distribution can be used to parametrize a multinomial, giving control over the smoothness or "uniformity" of the bins, e.g:

import numpy as np 

m = 50
n = 5
s = 0.1

np.random.multinomial(m, np.random.dirichlet(np.ones(n) * s))

mostly parameterised as @Bonfire, but larger values of s (e.g. try s=100) causing the bins to approach Poisson with mean=m/n and smaller values leading to greater variance

回答3:

Here is a sample solution:

import numpy as np

M = 50 # The fixed sum
N = 5 # The amount of numbers

array = np.random.multinomial(M, np.ones(N) / N)[0]
print(array)

来源：https://stackoverflow.com/questions/59148994/how-to-get-n-random-integer-numbers-whose-sum-is-equal-to-m

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