问题
I have a data.frame like this:
DqStr <- "Group q Dq SD.Dq
1 -3.0 0.7351 0.0067
1 -2.5 0.6995 0.0078
1 -2.0 0.6538 0.0093
2 -3.0 0.7203 0.0081
2 -2.5 0.6829 0.0094
2 -2.0 0.6350 0.0112"
Dq1 <- read.table(textConnection(DqStr), header=TRUE)
I would like to randomize group membership but only for rows with the same value of Dq1$q
g <-unique(Dq1$q)
Dq2<- data.frame()
for(n in g)
{
Dqq <- Dq1[Dq1$q==n,]
Dqq$Group <-sample(Dqq$Group)
Dq2 <- rbind(Dq2,Dqq)
}
That could also be done with plyr
library(plyr)
ddply(Dq1,.(q), function(x) { x$Group <- sample(x$Group)
data.frame(x)})
as I have to repeat this thousands times I wonder if there are a better (faster) way to do it.
回答1:
If I'm understanding your question correctly, this data.table
solution will also work:
library(data.table)
Dq1 <- as.data.table(Dq1)
Dq1[, Group := sample(Group), by = q]
Adding to Robert's benchmark above:
library(plyr)
library(data.table)
your_code <- function() { g <-unique(Dq1$q); Dq2<- data.frame(); for(n in g) { Dqq <- Dq1[Dq1$q==n,]; Dqq$Group <-sample(Dqq$Group); Dq2 <- rbind(Dq2,Dqq) } }
plyr_code <- function() { ddply(Dq1,.(q), function(x) { x$Group <- sample(x$Group); data.frame(x)}) }
base_code <- function() { Dq1$Group <- with(Dq1, ave(Group, q, FUN = sample)) }
data.table_code <- function() { Dq1 <- as.data.table(Dq1); Dq1[, Group := sample(Group), by = q] }
library(microbenchmark)
microbenchmark(your_code(), plyr_code(), base_code(), data.table_code())
Results:
Unit: milliseconds
expr min lq median uq max neval
your_code() 6.290822 6.771324 6.848123 6.966648 9.639748 100
plyr_code() 3.124676 3.307456 3.356095 3.455422 4.564390 100
base_code() 1.168874 1.301224 1.326055 1.348327 2.269652 100
data.table_code() 1.124844 1.157866 1.180649 1.209577 1.419750 100
For a data set this small, data.table is not clearly superior. But if you have many rows (and if you use fread
to read in your data as a data.table to start with), you'll see significant speedups over plyr, and some speedups over base R. So don't take this benchmark too seriously.
Edit: changed to use as.data.table()
instead of data.table()
, per Arun's comment.
回答2:
With base R, you could use ave
:
Dq1$Group <- with(Dq1, ave(Group, q, FUN = sample))
How fast is it?
library(plyr);
your_code <- function() { g <-unique(Dq1$q); Dq2<- data.frame(); for(n in g) { Dqq <- Dq1[Dq1$q==n,]; Dqq$Group <-sample(Dqq$Group); Dq2 <- rbind(Dq2,Dqq) } }
plyr_code <- function() { ddply(Dq1,.(q), function(x) { x$Group <- sample(x$Group); data.frame(x)}) }
base_code <- function() { Dq1$Group <- with(Dq1, ave(Group, q, FUN = sample)) }
library(microbenchmark)
microbenchmark(your_code(), plyr_code(), base_code())
Results:
Unit: microseconds
expr min lq median uq max neval
your_code() 745.592 855.3770 897.8580 956.0490 2981.026 100
plyr_code() 2054.471 2186.2665 2259.6075 2530.7875 4771.403 100
base_code() 216.323 239.0185 260.6925 282.8625 681.794 100
来源:https://stackoverflow.com/questions/25085537/permute-groups-in-a-data-frame-r