问题
To be more specific, how can i convert a scala.Iterable to a org.apache.spark.rdd.RDD ?
I have an RDD of (String, Iterable[(String, Integer)]) and i want this to be converted into an RDD of (String, RDD[String, Integer]), so that i can apply a reduceByKey function to the internal RDD.
e.g i have an RDD where key is 2-lettered prefix of a person's name and the value is List of pairs of Person name and hours that they spent in an event
my RDD is :
("To", List(("Tom",50),("Tod","30"),("Tom",70),("Tod","25"),("Tod",15))
("Ja", List(("Jack",50),("James","30"),("Jane",70),("James","25"),("Jasper",15))
i need the List to be converted to RDD so that i can use accumulate each person's total hours spent. Applying reduceByKey and make the result as
("To", RDD(("Tom",120),("Tod","70"))
("Ja", RDD(("Jack",120),("James","55"),("Jane",15))
But i counldn't find any such transformation function. How can i do this ?
Thanks in advance.
回答1:
You can achieve this by using a flatMap
and reduceByKey
. Something like this:
rdd.flatMap{case(key, list) => list.map(item => ((key,item._1), item._2))}
.reduceByKey(_+_)
.map{case((key,name),hours) => (key, List((name, hours)))}
.reduceByKey(_++_)
来源:https://stackoverflow.com/questions/37208871/how-to-convert-an-iterable-to-an-rdd