问题
I have a string like this: 100 Stupid Street ; Government Tower 7; Chicago Palm, MA 92111
I want to return all the characters to the left of the last semicolon.
To the left of the last semicolon would be: 100 Stupid Street ; Government Tower 7
That was step 1. I would also like to extract characters from this string: Chicago Palm, MA 92111
I want to return all the characters to the right and left of the second to last space.
So, To the right of the second to last space would be: MA 92111
To the left of the second to last space would be: Chicago Palm,
If there is a way to remove that last comma in that last formula, that would be even better.
This formula has helped me a bit:
=TRIM(RIGHT(SUBSTITUTE(A1,";",REPT(" ",LEN(A1))),LEN(A1)))
Cell A1 has the original string. This formula successfully returns everything to the right of the last semicolon.
回答1:
If you are looking to parse out all of the pieces, some of the previous returns can assist in the next operation(s) so portions of formulas do not have to be repeated.
B1 is =LEFT(SUBSTITUTE(A3, ";", "×",LEN(A3)-LEN(SUBSTITUTE(A3,";",""))), FIND("×",SUBSTITUTE(A3&"×", ";", "×",LEN(A3)-LEN(SUBSTITUTE(A3,";",""))))-1)
B2 is =TRIM(RIGHT(SUBSTITUTE(A2,";",REPT(" ",99)),99))
B3 is =TRIM(RIGHT(SUBSTITUTE(A3,",",REPT(" ",99)),99))
B4 is =TRIM(SUBSTITUTE(SUBSTITUTE(A4,B3,""),",",""))
回答2:
A shorter version:
B1 =LEFT(A1,(FIND(";",A1,FIND(";",A1)+1))-1) ==> 100 Stupid Street ; Government Tower 7
B2 =TRIM(RIGHT(A1,LEN(A1)-FIND(";",A1,FIND(";",A1)+1))) ==> Chicago Palm, MA 92111
B3 =LEFT(B2,FIND(",",B2)-1) ==> Chicago Palm
B4 =TRIM(RIGHT(B2,LEN(B2)-(FIND(",",B2)+1))) ==> MA 92111
More generic:
B1 =LEFT(A1,(FIND("^",SUBSTITUTE(A1,";","^",LEN(A1)-LEN(SUBSTITUTE(A1,";","")))))-1)
And performing substitutions can be achieved otherwise. Homework.
来源：https://stackoverflow.com/questions/26704318/excel-returning-characters-to-the-left-and-right-of-the-last-or-second-to-last