Grouping Parametrized Benchmarks with pytest

问题

I'm currently benchmarking an implementation of an AVL Tree I made against a non-rebalancing binary search tree using pytest-benchmark. It seems to be working well for me so far but I've run into an issue. In order to consolidate the test file, I found that I can parametrize tests and also group the output of the benchmark for readability but I can't seem to do them both at the same time.

My current insertion benchmark:

# always the same for repeatability
random.seed(0x1C2C6D66)

def insertRandomOrder(t, n):
  tree = t()
  for i in range(0,n):
    tree.insert(random.randint(0,0x7FFFFFFF),i)

def insertDescendingOrder(t, n):
  tree = t()
  for i in range(0,n):
    tree.insert(n-i,i)

def insertOutInOrder(t, n):
  tree = t()
  for i in range(0,n):
    idx = (i%2)*n + (1-2*(i%2))*i
    tree.insert(idx,i)

def insertAscendingOrder(t, n):
  tree = t()
  for i in range(0,n):
    tree.insert(i,i)

types = [BaseTree, AvlTree]
sizes = [100,300,1000]
cases = [insertAscendingOrder, insertDescendingOrder, insertOutInOrder, insertRandomOrder]

@pytest.mark.parametrize('t', types)
@pytest.mark.parametrize('n', sizes)
@pytest.mark.parametrize('case', cases)
def test_insert_benchmark(benchmark, t, n, case):
  benchmark(case, t, n)

And here is the output:

Does anyone know of a way where I could group the output but say, the case from my example? Or better yet, by a (case,n) tuple?

回答1:

There was a useful comment saying that the master branch of pytest is in the process of supporting this exact feature, but I was unable to get it to work (fingers crossed for next release).

In the meantime, I figured out this handy work around. I'm able to group by case, but not by (case,n) with this method. I added a @benchmark_this decorator above each test case to wrap the benchmark call. It's pretty handy even without the extra benefit of grouping by test case!

def benchmark_this(test):
  def wrapper(benchmark, t, n):
    benchmark(test, None, t, n)
  return wrapper

types = [BaseTree, AvlTree]
sizes = [100,300,1000]

@pytest.mark.parametrize('t', types)
@pytest.mark.parametrize('n', sizes)
@benchmark_this
def test_insertRandomOrder(benchmark, t, n):
  random.seed(0x1C2C6D66)
  tree = t()
  for i in range(n):
    tree.insert(random.randint(0, 0x7FFFFFFF), i)

@pytest.mark.parametrize('t', types)
@pytest.mark.parametrize('n', sizes)
@benchmark_this
def test_insertDescendingOrder(benchmark, t, n):
  tree = t()
  for i in range(n):
    tree.insert(n-i, i)

# ...

Invoked with

py.test --benchmark-group-by=func

来源：https://stackoverflow.com/questions/35110308/grouping-parametrized-benchmarks-with-pytest

标签

python

pytest