Convert XMLHttpRequest to python requests

问题

I found an XHR request for a website, now I want to convert this request to corresponding python/requests code and struggled at how to parse the responseType to corresponding replacement code, here is the download script:

const download = (url, params = {}, dowType, name, img, method) =>
    new Promise((resolve, reject) => {
        const _tmpArr = Object.keys(params) || [];
        const _formData = new FormData();

        _tmpArr.map(value => {
            if (params[value] || params[value] === 0 || params[value] === '') {
                _formData.append(value, params[value]);
            }
        });

        let xhr = new XMLHttpRequest();
        xhr.open('POST', url, true);
        xhr.responseType = 'blob';
        xhr.onload = function(e) {
            if (this.status === 200) {
                const reader = new FileReader();

                reader.onload = event => {
                    //....
                };
                reader.readAsText(this.response);
            }
            if (!img) {
                resolve();
            }
        };
        xhr.send(_formData);
    });

download('http://the/post/url', {
    sampleNo
})

Since I didn't write javascript code mainly and didn't get any helps from mozilla docs about the blob, then I copied to the corresponding curl command via Copy as cURL function in Chrome's network inspector, here is the command text:

curl 'http://the/post/url' \
  -H 'Connection: keep-alive' \
  -H 'User-Agent: Mozilla/5.0 (Macintosh; Intel Mac OS X 10_15_5) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/83.0.4103.106 Safari/537.36' \
  -H 'Content-Type: multipart/form-data; boundary=----WebKitFormBoundarybfGJ0I90Seu9Ywjc' \
  -H 'Accept: */*' \
  -H 'Origin: http://www.example.com' \
  -H 'Referer: http://www.example.com/reports/' \
  -H 'Accept-Language: en-US,en;q=0.9,zh-CN;q=0.8,zh;q=0.7,zh-TW;q=0.6' \
  --data-binary $'------WebKitFormBoundarybfGJ0I90Seu9Ywjc\r\nContent-Disposition: form-data; name="sampleNo"\r\n\r\nXFFFFFF000000\r\n------WebKitFormBoundarybfGJ0I90Seu9Ywjc--\r\n' \
  --compressed \
  --insecure

For the following version of python code, it sends the post request with multipart-formdata to the service and a logic service error returns (the status code is 200, but the response data is {'code': '000001', 'msg': 'internal system exception', 'data': 'getInputStream() has already been called for this request'}, this is a Java related exception from server side and it confirms the request data shall(?) get received).

I tries to update the Accept header value to blob, */blob, application/octet-stream, application/python-pickle and others, none of them work, it returns 500 error directly. So I wonder what's the right replacement about the responseType with blob in XHR request.

import os
import logging
import requests
from requests_toolbelt import MultipartEncoder

logging.basicConfig(level=logging.DEBUG)

def download(order_id):

    url = "http://the/post/url"
    m = MultipartEncoder(fields={'sampleNo': order_id})
    headers = {
        'Connection': 'keep-alive',
        'User-Agent': 'Mozilla/5.0 (Macintosh; Intel Mac OS X 10_15_5) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/83.0.4103.106 Safari/537.36',
        'Accept': '*/*',
        'Origin': 'http://www.example.com',
        'Referer': 'http://www.example.com/reports/.....',
        'Accept-Language': 'en-US,en;q=0.9,zh-CN;q=0.8,zh;q=0.7,zh-TW;q=0.6',
        'dnt': '1',
        'Content-Type': m.content_type,
    }

    try:
        logging.info('Downloading report %s' % order_id)
        response = requests.post(url, data=m, headers=headers)

        if response.status_code != requests.codes.OK:
            logging.error(response.content)
            return False

        json_data = response.json()

        if json_data.get('code') != '000000':
            logging.error(json_data)
            return False

        with open(filepath, 'wb') as f:
            f.write(response.content)

        logging.info('Downloaded report to %s' % filepath)
    except Exception as e:
        logging.exception(e)
        return False

    return True

来源：https://stackoverflow.com/questions/62538257/convert-xmlhttprequest-to-python-requests