问题
When defining a function in pure Python, its signature is visible when calling help
. For example:
>>> def hello(name):
... """Greet somebody."""
... print "Hello " + name
...
>>> help(hello)
Help on function hello in module __main__:
hello(name)
Greet somebody.
>>>
When defining a Python function in C/API, though, its signature lacks basic information:
static PyObject*
mod_hello(PyObject* self, PyObject* args)
{
const char* name;
if (!PyArg_ParseTuple(args, "s", &name))
return NULL;
printf("Hello %s\n", name);
Py_RETURN_NONE;
}
static PyMethodDef HelloMethods[] =
{
{"hello", mod_hello, METH_VARARGS, "Greet somebody."},
{NULL, NULL, 0, NULL}
};
This yields:
>>> help(hello)
Help on built-in function hello in module hello:
hello(...)
Greet somebody.
Any ideas how, in C/API, to change the signature from hello(...)
to hello(name)
?
回答1:
You can include the signature by prepending it to the function docstring in a way that inspect
can extract them (at least it works for Python 3.4+):
static PyMethodDef HelloMethods[] =
{
{"hello", mod_hello, METH_VARARGS, "hello(name, /)\n--\n\nGreet somebody."},
{NULL, NULL, 0, NULL}
};
Note I've posted a more complete answer here that explain the rules and mechanics in some more depth.
来源:https://stackoverflow.com/questions/38818400/specifying-python-function-signature-in-c-api