问题
Here I have defined my data myListOfEmployeeObjects:
public class App : Application
{
public List<Employee> myListOfEmployeeObjects;
public App ()
{
Employee emp1 = new Employee () {
FirstName = "Max",
LastName = "Mustermann",
Twitter = "@fake1"
};
Employee emp2 = new Employee () {
FirstName = "Evy",
LastName = "Mustermann",
Twitter = "@fake2"
};
myListOfEmployeeObjects = new List<Employee> {
emp1, emp2
};
MainPage = new NavigationPage (new EmployeeListPage ());
}
}
Than I have my XAML where I set the ItemsSource
:
<ListView x:Name="listView"
IsVisible="false"
ItemsSource="{x:Static local:App.myListOfEmployeeObjects}"
ItemSelected="EmployeeListOnItemSelected">
Should this work? Because I get
Xamarin.Forms.Xaml.XamlParseException: Type App not found in xmlns
public partial class EmployeeListPage : ContentPage {
private ListView listView;
private void InitializeComponent() {
this.LoadFromXaml(typeof(EmployeeListPage)); // here the exception is thrown
listView = this.FindByName <ListView>("listView");
}
}
How can I set the ItemsSource
of my XAML?
Edit:
Now I tried the suggestion from user2425632 and it works if I do the following changes:
- Adding
xmlns:local="clr-namespace:HelloXamarinFormsWorld;assembly=HelloXamarinFormsWorld"
to my XAML file
It now looks like the following
<?xml version="1.0" encoding="UTF-8"?>
<ContentPage xmlns="http://xamarin.com/schemas/2014/forms"
xmlns:x="http://schemas.microsoft.com/winfx/2009/xaml"
xmlns:local="clr-namespace:HelloXamarinFormsWorld;assembly=HelloXamarinFormsWorld"
x:Class="HelloXamarinFormsWorld.EmployeeListPage"
Title="Employee List">
<ContentPage.Content>
Of course you have to change the names so that it suits to your project.
- Showing list view
I removed the IsVisible
and the ItemSelected
.
<ListView ItemsSource="{x:Static local:App.myListOfEmployeeObjects}">
- Make everything static
It has to be static, otherwise you get
No static member found for local:App.myListOfEmployeeObjects
public static List<Employee> myListOfEmployeeObjects { private set; get; }
public static void GetAllEmployees(){
Employee emp1 = new Employee () {
FirstName = "Max",
LastName = "Mustermann",
Twitter = "@fake1"
};
Employee emp2 = new Employee () {
FirstName = "Eva",
LastName = "Mustermann",
Twitter = "@fake2"
};
myListOfEmployeeObjects = new List<Employee> {
emp1, emp2
};
}
public App ()
{
GetAllEmployees ();
MainPage = new NavigationPage (new EmployeeListPage ());
}
回答1:
So I haven't actually gotten around to doing this myself but from reading the documentation I have a suggestion which may be worth you trying.
ItemsSource="{x:Static local:App.myListOfEmployeeObjects}"
In your xaml you've said that the source is static but looking at your .cs file it isn't. Try the following:
public static List<Employee> myListOfEmployeeObjects { private set; get; }
and then try and set the object using a static function, eg.:
static App() {
myListOfEmployeeObjects = something;
}
Then the list should be viewable on the page.
I used the following links which you may find useful:
Xamarin documentation on data-binding
Example cs code
Example xaml code
Hope that helps.
回答2:
I think I have the solution for your problem. I had the same issue and I added this line in EmployeeListPage.xaml :
xmlns:local="clr-namespace:YourNamespace;assembly=YourAssembly"
You'll get the name of assembly in the properties of your project and the namespace in any page.cs
回答3:
You can use ObservableCollections
. This type of collection, notifies when changes are made to it.
In your code:
.cs:
public class YourClass : INotifyPropertyChanged //Note this INotifyPropertyChanged
{
private ObservableCollection<Employee> _myListOfEmployeeObjects;
public ObservableCollection<Employee> ObservableEmployees
{
get
{
if (_myListOfEmployeeObjects == null) LoadEmployees();
return _myListOfEmployeeObjects;
}
set
{
_myListOfEmployeeObjects = value;
OnPropertyChanged("ObservableEmployees");
}
}
private void LoadEmployees()
{
// Necessary stuff to load employees
ObservableEmployees = new ObservableCollection<Employees>();
....
}
You must add a DataContext = this
in your default constructor:
public YourClass()
{
InitializeComponent();
DataContext = this;
}
And then, add the necessary method to NotifyOnPropertyChanged
:
protected virtual void OnPropertyChanged(string propertyName)
{
PropertyChangedEventHandler handler = PropertyChanged;
if (handler != null) handler(this, new PropertyChangedEventArgs(propertyName));
}
In your .xaml:
<ListView x:Name="listView"
IsVisible="false"
ItemsSource="{Binding Path=ObservableEmployees, ElementName=EmployeesWindow, NotifyOnSourceUpdated=True}"
ItemSelected="EmployeeListOnItemSelected">
In ElementName=EmployeesWindow
, the EmployeesWindow
is your main Window x:Name
.
<Window ...
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
Name="EmployeesWindow" >
来源:https://stackoverflow.com/questions/28738090/how-to-set-itemssource-of-listview