Show all methods of a function in Julia

一世执手 提交于 2021-01-26 04:46:21

问题


How can I show all the methods of a function in Julia (multiple dispatch)?

For example, all the methods that exist in the namespace for the function abs.


回答1:


The methods function will return the method table for the given function:

julia> methods(abs)
# 13 methods for generic function "abs":
[1] abs(a::Pkg.Resolve.FieldValue) in Pkg.Resolve at /home/david/pkg/julia-bin/julia-1.4.0-rc1/share/julia/stdlib/v1.4/Pkg/src/Resolve/fieldvalues.jl:61
[2] abs(a::Pkg.Resolve.VersionWeight) in Pkg.Resolve at /home/david/pkg/julia-bin/julia-1.4.0-rc1/share/julia/stdlib/v1.4/Pkg/src/Resolve/versionweights.jl:36
[3] abs(::Missing) in Base at missing.jl:100
[4] abs(x::Float64) in Base at float.jl:528
...

As of Julia 1.4, you can filter the method table by module. For example, listing the methods of abs which were defined in the Dates module:

julia> methods(abs, Dates)
# 1 method for generic function "abs":
[1] abs(a::T) where T<:Dates.Period in Dates at /home/david/pkg/julia-bin/julia-1.4.0-rc1/share/julia/stdlib/v1.4/Dates/src/periods.jl:95


来源:https://stackoverflow.com/questions/60694318/show-all-methods-of-a-function-in-julia

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