问题
I have an int array (b[])
with a random length and random integers. I want to leave integers lower than 9 to how they are, i want to change the numbers 9-35
to letters A-Z
. and i want do put ()
around all numbers higher than 35
. So b[] = {1,10,36}
would generate a String 1A(36)
. My try:
int b[] = {99, 2, 3, 4, 5, 10, 35, 24}; //sample input
char[] hilfsarray = new char[b.length];
char[] alphabet = "ABCDEFGHIJKLMNOPQRSTUVW".toCharArray();
for (int k = 0; k < hilfsarray.length; k++) //overwrite all positons with *
hilfsarray[k] = '*';
for (int i = 0; i < b.length; i++) {
int p = b[0] - 10;
if (b[i] < 9 && b[i] <= 35) {
hilfsarray[i] = alphabet[p];
}
return Arrays.toString(hilfsarray);
}
回答1:
I think this code will do your job. It uses Java-8, StreamAPI:
public String someMethod() {
int[] items = {99, 2, 3, 4, 5, 10, 35, 24}; // sample input
String[] alphabet =
"A,B,C,D,E,F,G,H,I,J,K,L,M,N,O,P,Q,R,S,T,U,V,W,X,Y,Z".split(",");
return Arrays.stream(items)
.mapToObj(item -> (item > 9 && item <= 35) ?
alphabet[item - 10] : "(" + item + ")")
.reduce("", String::concat);
}
Sample output:
(99)(2)(3)(4)(5)AZO
回答2:
You can interpret numbers in the range 10-35
as characters and shift their code points by 55
to get code points of uppercase letters 65-90
:
public static void main(String[] args) {
int[] a = {1, 10, 36};
int[] b = {99, 2, 3, 4, 5, 10, 35, 24};
System.out.println(custom(a)); // 1A(36)
System.out.println(custom(b)); // (99)2345AZO
}
public static String custom(int[] arr) {
return Arrays.stream(arr).mapToObj(i -> {
if (i > 9 && i < 36)
return Character.toString(i + 55);
else if (i > 35)
return "(" + i + ")";
else
return String.valueOf(i);
}).collect(Collectors.joining());
}
See also: Replace non ASCII character from string
来源:https://stackoverflow.com/questions/65130666/change-numbers-to-letters-in-a-int-array-and-return-string-in-java