问题
I want to fix the position of pop-up menu in QML. When I click on a setting button,I want the pop-up menu will display at the fixed position. I did it by a day but can't. How can I do it in QML. Also, I want to change the size of menu item(width and Height).
Hope your help!
回答1:
That depends on QtQuick.Controls
version.
In 2.0
you can define size and position(and even more - you must do)
import QtQuick 2.7
import QtQuick.Controls 2.0
//import QtQuick.Controls 1.4
import QtQuick.Window 2.0
Window
{
id: window
width: 500
height: 500
visible: true
MouseArea {
anchors.fill: parent
onClicked: {
menu.x = (window.width - menu.width) / 2
menu.y = (window.height - menu.height) / 2
//menu.__popup(Qt.rect(200,200,100,100),0,0);
menu.open();
}
}
Menu {
id: menu
MenuItem { text: "item1" }
MenuItem { text: "item2"; }
MenuItem { text: "item3"; height: 100 }
}
}
In 1.4
(see commented lines) you can try Menu.__popup()
but this function is private and the behavior is unpredictable.
来源:https://stackoverflow.com/questions/38580053/how-can-set-pop-up-menu-position-in-qml