How to find Linux Distribution name using shell script?

问题

I am writing a shell script in which I need the current operating system name to make it generic. Like:

if [ $Operating_System == "CentOS" ]
then
    echo "CentOS";
    # Do this
elif [ $Operating_System == "Ubuntu" ]
then
    echo "Ubuntu";
    # Do that
else
    echo "Unsupported Operating System";
fi

How will it be possible? Applying regular expression on lsb_release -a command or something else?

Thanks..

回答1:

$ lsb_release -i
Distributor ID: Fedora
$ lsb_release -i | cut -f 2-
Fedora

回答2:

You can get the info from lsb_release:

echo "$(lsb_release -is)"

i stands for distributor id.

s stands for short.

For ex. It shows Ubuntu instead of Distributor Id: Ubuntu

There are other options:

-r : release

-d : description

-c : codename

-a : all

You can get this information by running lsb_release --help or man lsb_release

回答3:

try this one:

awk '/^ID=/' /etc/*-release | awk -F'=' '{ print tolower($2) }'

回答4:

DISTRO=$( cat /etc/*-release | tr [:upper:] [:lower:] | grep -Poi '(debian|ubuntu|red hat|centos|nameyourdistro)' | uniq )
if [ -z $DISTRO ]; then
    DISTRO='unknown'
fi
echo "Detected Linux distribution: $DISTRO"

回答5:

For almost all linux distros, cat /etc/issue will do the trick.

Edit: Obviously, no solution can apply to all distros, as distros are free to do as they please.

Further clarification: This is not guaranteed to work - nothing is - but in my experience, this is the method that most often works. Actually, it's the only method that works consistently (lsb_release, which was mentioned here, often produces command not found).

回答6:

Here is what i get:

#!/bin/bash

dist=$(tr -s ' \011' '\012' < /etc/issue | head -n 1)

check_arch=$(uname -m)

echo "[$green+$txtrst] Distribution Name: $dist"

回答7:

I'd use uname -a

robert@debian:/tmp$ uname -a
Linux debian 3.2.0-4-686-pae #1 SMP Debian 3.2.65-1+deb7u2 i686 GNU/Linux

来源：https://stackoverflow.com/questions/29581754/how-to-find-linux-distribution-name-using-shell-script

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