问题
I'm learning Python (slowly but surely) but need to write a program that (among other things) increments between two hex values e.g. 30D681 and 3227FF. I'm having trouble finding the best way to do this. So far I have seen a snippet of code on here that separates the hex into 30, D6 and 81, then works like this-
char = 30
char2 = D6
char3 = 81
def doublehex():
global char,char2,char3
for x in range(255):
char = char + 1
a = str(chr(char)).encode("hex")
for p in range(255):
char2 = char2 + 1
b = str(chr(char2)).encode("hex")
for y in range(255):
char3 = char3 + 1
b = str(chr(char2)).encode("hex")
c = a+" "+b
print "test:%s"%(c)
doublehex()
Is there a simpler way of incrementing the whole value, e.g. something like
char = 30D681
char2 = 3227FF
def doublehex():
global char,char2
for x in range(255):
char = char + 1
a = str(chr(char)).encode("hex")
for p in range(255):
char2 = char2 + 1
b = str(chr(char2)).encode("hex")
c = a+" "+b
print "test:%s"%(c)
doublehex()
Apologies for my complete ignorance, I really have tried Googling the answer but couldn't find it...
回答1:
Just treat the values as integers, and use xrange()
to range over the two values. Use format(value, 'X')
to display it as hex:
start = 0x30D681 # hex literal, gives us a regular integer
end = 0x3227FF
for i in xrange(start, end + 1):
print format(i, 'X')
If your start and end values were entered as hexadecimal strings, use int(hexvalue, 16)
to turn those into integers first:
start = int('30D681', 16)
end = int('3227FF', 16)
来源:https://stackoverflow.com/questions/16212965/incrementing-iterating-between-two-hex-values-in-python