问题
I have the following data:
pd.DataFrame({'Group_ID':[1,1,1,2,2,2,3,4,5,5],
'Item_id':[1,2,3,4,5,6,7,8,9,10],
'Target': [0,0,1,0,1,1,0,0,0,1]})
Group_ID Item_id Target
0 1 1 0
1 1 2 0
2 1 3 1
3 2 4 0
4 2 5 1
5 2 6 1
6 3 7 0
7 4 8 0
8 5 9 0
9 5 10 1
I need to split the dataset into a training and testing set based on the "Group_ID" so that 80% of the data goes into a training set and 20% into a test set.
That is, I need my training set to look something like:
Group_ID Item_id Target
0 1 1 0
1 1 2 0
2 1 3 1
3 2 4 0
4 2 5 1
5 2 6 1
6 3 7 0
7 4 8 0
And test set:
Test Set
Group_ID Item_id Target
8 5 9 0
9 5 10 1
What would be the simplest way to do this? As far as I know, the standard test_train_split function in sklearn does not support splitting by groups in a way where I can also indicate the size of the split (e.g. 80/20).
回答1:
I figured out the answer. This seems to work:
train_inds, test_inds = next(GroupShuffleSplit(test_size=.20, n_splits=2, random_state = 7).split(df, groups=df['Group_Id']))
train = df.iloc[train_inds]
test = df.iloc[test_inds]
来源:https://stackoverflow.com/questions/54797508/how-to-generate-a-train-test-split-based-on-a-group-id