Laravel: How to get last N entries from DB

问题

I have table of dogs in my DB and I want to retrieve N latest added dogs.

Only way that I found is something like this:

Dogs:all()->where(time, <=, another_time);

Is there another way how to do it? For example something like this Dogs:latest(5);

Thank you very much for any help :)

回答1:

You may try something like this:

$dogs = Dogs::orderBy('id', 'desc')->take(5)->get();

Use orderBy with Descending order and take the first n numbers of records.

回答2:

My solution for cleanliness is:

Dogs::latest()->take(5)->get();

It's the same as other answers, just with using built-in methods to handle common practices.

回答3:

Dogs::orderBy('created_at','desc')->take(5)->get();

回答4:

You may also try like this:

$recentPost = Article::orderBy('id', 'desc')->limit(5)->get();

It's working fine for me in Laravel 5.6

回答5:

You can pass a negative integer n to take the last n elements.

Dogs::all()->take(-5)

This is good because you don't use orderBy which is bad when you have a big table.

回答6:

Ive come up with a solution that helps me achieve the same result using the array_slice() method. In my code I did array_slice( PickupResults::where('playerID', $this->getPlayerID())->get()->toArray(), -5 ); with -5 I wanted the last 5 results of the query.

来源：https://stackoverflow.com/questions/24860973/laravel-how-to-get-last-n-entries-from-db