今天总结一下关于DataTable,XML转JSON的方法:
首先需要引入命名空间: using Newtonsoft.Json 1 public string DataTableToJsonWithStringBuilder(DataTable table)
2 {
3 var jsonString = new StringBuilder();
4 if (table.Rows.Count > 0)
5 {
6 jsonString.Append("[");
7 for (int i = 0; i < table.Rows.Count; i++)
8 {
9 jsonString.Append("{");
10 for (int j = 0; j < table.Columns.Count; j++)
11 {
12 if (j < table.Columns.Count - 1)
13 {
14 jsonString.Append("\"" + table.Columns[j].ColumnName.ToString()
15 + "\":" + "\""
16 + table.Rows[i][j].ToString() + "\",");
17 }
18 else if (j == table.Columns.Count - 1)
19 {
20 jsonString.Append("\"" + table.Columns[j].ColumnName.ToString()
21 + "\":" + "\""
22 + table.Rows[i][j].ToString() + "\"");
23 }
24 }
25 if (i == table.Rows.Count - 1)
26 {
27 jsonString.Append("}");
28 }
29 else
30 {
31 jsonString.Append("},");
32 }
33 }
34 jsonString.Append("]");
35 }
36 return jsonString.ToString();
37 }
调用:
var xmlToJson = DataTableToJsonWithStringBuilder(newdt);// datatable转json数组
//XML转JSON
var xmlToJson1 = JsonConvert.SerializeXmlNode(child, Newtonsoft.Json.Formatting.None, true);
来源:oschina
链接:https://my.oschina.net/u/4387051/blog/4423084