How do you determine which network interface is connected to the internet using Java? For example, I run
InetAddress.getLocalHost().getHostAddress();
and within Eclipse this returns exactly what I intend, 192.168.1.105. However, if I package this into a jar file and run the program, the code returns 169.254.234.50. Looking into this, I found this is the IP address of a VMware Virtual Ethernet Adapter interface on my machine.
Is there any way to determine the interface connected to the internet, yet at the same time maintain portability for my code?
Comparison of Interfaces
Interface [net4]
display name : Intel(R) Centrino(R) Ultimate-N 6300 AGN
MTU : 1500
loopback : false
point to point: false
up : true
virtual : false
multicast : true
HW address : 00 24 D7 2C 5F 70
INET address (IPv4): 192.168.1.105
host name : MyComputer
canonical host name : MyComputer
loopback : false
site local : true
any local : false
link local : false
multicast : false
reachable : true
Interface [eth5]
display name : VMware Virtual Ethernet Adapter for VMnet1
MTU : 1500
loopback : false
point to point: false
up : true
virtual : false
multicast : true
HW address : 00 50 56 C0 00 01
INET address (IPv4): 169.254.234.50
host name : MyComputer
canonical host name : MyComputer
loopback : false
site local : false
any local : false
link local : true
multicast : false
reachable : true
There's a third VMware interface with site local=true and link local=false, so those fields aren't any help either.
On my laptop (running Windows 7, with Virtual Box and it's network interface installed) the following code prints out the name of my wireless interface along with my local address. It uses a brute force approach at the end of the day, but will only try and actually connect to addresses that are considered to be the best candidates.
// iterate over the network interfaces known to java
Enumeration<NetworkInterface> interfaces = NetworkInterface.getNetworkInterfaces();
OUTER : for (NetworkInterface interface_ : Collections.list(interfaces)) {
// we shouldn't care about loopback addresses
if (interface_.isLoopback())
continue;
// if you don't expect the interface to be up you can skip this
// though it would question the usability of the rest of the code
if (!interface_.isUp())
continue;
// iterate over the addresses associated with the interface
Enumeration<InetAddress> addresses = interface_.getInetAddresses();
for (InetAddress address : Collections.list(addresses)) {
// look only for ipv4 addresses
if (address instanceof Inet6Address)
continue;
// use a timeout big enough for your needs
if (!address.isReachable(3000))
continue;
// java 7's try-with-resources statement, so that
// we close the socket immediately after use
try (SocketChannel socket = SocketChannel.open()) {
// again, use a big enough timeout
socket.socket().setSoTimeout(3000);
// bind the socket to your local interface
socket.bind(new InetSocketAddress(address, 8080));
// try to connect to *somewhere*
socket.connect(new InetSocketAddress("google.com", 80));
} catch (IOException ex) {
ex.printStackTrace();
continue;
}
System.out.format("ni: %s, ia: %s\n", interface_, address);
// stops at the first *working* solution
break OUTER;
}
}
(I've updated my answer with isReachable(...)
based on Mocker Tim's answer.)
One thing to watch out for. socket.bind(...)
would bark at me that the address and port is already in use if I tried to run my code too fast in succession like the connection isn't cleaned up fast enough. 8080
should be a random port maybe.
Take a look at Retrieving Network Interfaces and Listing Network Interface Addresses in the Java Tutorial.
If you have several network interfaces which are up and running, you must select programmatically the network interface that your program should use.
UPDATE:
I've found the question that is similar to yours.
See the answer to how-to-check-if-internet-connection-is-present-in-java.
UPDATE 2:
IMHO You should do the following in your program:
- Find all IPv4 network interfaces on the machine that your program is running on;
- Ask the user which of them your program should use;
- Use the interface, that the user pointed to.
I was having the same problem, and came up with this solution (not as thorough as the answer, but I needed something that didn't try to connect to the internet.
Based on known OUI for mac addresses: http://standards-oui.ieee.org/oui.txt
I made a quick check (could be optimized with binary logic)
private static boolean isVmwareMac(byte[] mac) {
byte invalidMacs[][] = {
{0x00, 0x05, 0x69}, //VMWare
{0x00, 0x1C, 0x14}, //VMWare
{0x00, 0x0C, 0x29}, //VMWare
{0x00, 0x50, 0x56} //VMWare
};
for (byte[] invalid: invalidMacs){
if (invalid[0] == mac[0] && invalid[1] == mac[1] && invalid[2] == mac[2])
return true;
}
return false;
}
I was bugged by the same problem for a quite a bit and eventhough the inital question was asked ages ago I'll append my take on ths issue anyway.
The ironic thing is that the answer was provided along with the question.
It is: siteLocal = true
Here is what worked for me
Get all network interfaces
NetworkInterface.getNetworkInterfaces();
Single out those that are currently down (just reduces the number of runs)
if(interface.isUp()){}
Get the InetAddresses of the interfaces you just singled out
interface.getInetAddresses();
Check those addresses if they are site local addresses
if(inetAddress.isSiteLocal()){}
That should give you one/all InetAddress(es) - and the network interface(s) that is/are linked to your local network.
Site local is defined to use addresses from these networks: 10.0.0.0, 172.16.0.0, 192.168.0.0 while VirtualBox adapters and others usually use the 169.254.0.0 link-local addresses.
IPv6 also implements the site local concept, so it's best to focus on IPv4 here.
On a regular end user machine this should work rather well and return just the one physical interface.
来源:https://stackoverflow.com/questions/8462498/how-to-determine-internet-network-interface-in-java