Getting a variable from the caller's globals. What is a frame object?

浪尽此生 提交于 2020-08-08 05:00:09

问题


The documentation for the inspect module says:

When the following functions return “frame records,” each record is a named tuple FrameInfo(frame, filename, lineno, function, code_context, index). The tuple contains the frame object, the filename, the line number of the current line, the function name, a list of lines of context from the source code, and the index of the current line within that list.

What is actually a "frame object"? I was hoping to use this frame object to get a variable's value from the caller's globals():

import my_util

a=3
my_util.get_var('a')

and my_util.py

import inspect

def get_var(name):
    print(inspect.stack()[1][0])

回答1:


from https://docs.python.org/3/library/inspect.html#types-and-members:

frame   f_back      next outer frame object (this frame’s caller)
        f_builtins  builtins namespace seen by this frame
        f_code      code object being executed in this frame
        f_globals   global namespace seen by this frame
        f_lasti     index of last attempted instruction in bytecode
        f_lineno    current line number in Python source code
        f_locals    local namespace seen by this frame
        f_restricted    0 or 1 if frame is in restricted execution mode
        f_trace     tracing function for this frame, or None

therefore to get some globals in your my_util.py:

import inspect

def get_var(name):
    print(inspect.stack()[1][0].f_globals[name])


来源:https://stackoverflow.com/questions/44107877/getting-a-variable-from-the-callers-globals-what-is-a-frame-object

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