问题
Using scientific notation for floating point literals is easy enough in Fortran:
1.5d-10
would mean a double precision (whatever that means under current Fortran compiler settings) floating point value that approximates 1.5*10^-15
.
However, the fusion of the exponent notation and the floating point kind specifier is a bit of an issue. How would one declare this floating point literal when one wants it to have a type of C_DOUBLE
?
I know that this is a bit of a nitpicking issue, but there can be circumstances when double precision will not be the same as C_DOUBLE
.
回答1:
A real literal may be specified by any of the following forms:
1.2
1.2e0
1.2d0
1.2_kind
1.2e0_kind
This final one is an example of using a kind specifier and an exponent. So, specific to the question: 1.5e-15_C_DOUBLE
.
There certainly can be cases where 1.5d-15
is not the same as 1.5e-15_C_DOUBLE
. The kind of a double precision and real(C_DOUBLE)
are choices by the Fortran and companion C compilers respectively.
Compilers which allow single and double precision literal constants to be promoted to higher kinds by a compiler flag won't touch real(C_DOUBLE)
.
来源:https://stackoverflow.com/questions/49956241/using-scientific-notation-and-underscore-kind-specifier-at-the-same-time-for-rea