shell script relative position from the file

问题

I have almost no idea about shell scripts or commands in linux

I have a project named projectx

projectX happens to be in users/hardik/desktop/projectx

I have created a shell script start.sh. This is the content of shell script

echo "Starting typescript build in new terminal.."

osascript -e 'tell application "Terminal" to do script "npm run build"' 

sleep 3

echo "Starting firebase functions...."

osascript -e 'tell application "Terminal" to do script "firebase emulators:start --only functions"'


echo "Process compelete.. Check if there were two terminals window open"

now this works but say here

osascript -e 'tell application "Terminal" to do script "npm run build"'

it runs that in the root and hence gives the following error

ENOENT: no such file or directory, open /Users/hardik/package.json

How can I make it execute in the path which is relative to start.sh

Update: I tried this

echo "Starting typescript build in new terminal.."
path=`pwd`
osascript -e 'tell application "Terminal" to do script "cd ${path} npm run watch:scss"' 
osascript -e 'tell application "Terminal" to do script "npm run watch"'

echo "Process compelete.. Check if there were two terminals window open"

but this didn't work with error cd: too many arguments

回答1:

Just change directory to where you need to be prior to running npm:

osascript -e 'tell application "Terminal" to do script "cd /Users/somewhere && npm run build"'

回答2:

Insert the line:

cd `dirname $0`

at the top of start.sh. The dirname command produces the directory that a file contains, and $0 is the path that invoked start.sh, so that's the relative directory that you wanted. Note those quotes a left-quotes, so the result of running dirname is passed to cd.

来源：https://stackoverflow.com/questions/62658602/shell-script-relative-position-from-the-file