问题
I recently answered a question where a user was having trouble because they were appending a multi-dimensional array to another array, and it was brought to my attention in my answer that it is possible to use iterable unpacking to populate an x and y value and assign to board[x][y] on the same line.
I had expected this to throw an error as x and y had at the time not been defined, as, even in the iterable-unpacking tag it reads:
elements of an iterable are simultaneously assigned to multiple values
This can be seen as working in the following example:
>>> board = [[0, 0], [0, 0]]
>>> move = [0, 1, 2]
>>> x, y, board[x][y] = move
>>> board
[[0, 2], [0, 0]]
Which is the same as:
>>> board = [[0, 0], [0, 0]]
>>> move = [0, 1, 2]
>>> x = move[0]
>>> y = move[1]
>>> board[x][y] = move[2]
>>> board
[[0, 2], [0, 0]]
And yet when calculating the Fibonacci sequence using:
a, b = b, a + b
It doesn't evaluate as:
a = b
b = a + b
And when swapping values with:
a, b = b, a
It doesn't evaluate as:
a = b
b = a
So why does this work in the first example?
回答1:
The right side of the = is always evaluated first, in this case it is packing a tuple. That tuple is then unpacked when interpreting the left hand side. The left and right sides do not share knowledge of variables. The RHS becomes a value and then the LHS uses that value to assign to the variables (labels).
In your example the values of x and y are determined after the RHS is evaluated. The unpacking then occurs left to right, so that board[x][y] has valid indices.
Switching the order demonstrates the unpacking sequence:
>>> board[x][y], x, y = move[2], move[0], move[1]
---------------------------------------------------------------------------
NameError Traceback (most recent call last)
<ipython-input-7-a984ef3168f8> in <module>()
----> 1 board[x][y], x, y = move[2], move[0], move[1]
NameError: name 'x' is not defined
来源：https://stackoverflow.com/questions/47842352/iterable-unpacking-evaluation-order