variable-assignment

mysql user variable assignement with count(*)

落爺英雄遲暮 提交于 2021-02-17 06:54:19
问题 I try to do query with a user variable, but I don't understand why, i can't update the variable in the query. I want to sum the grouped result for each day to do a chart. That really simple. SET @total := 0; SELECT "total Register", li.registerDate, @total := COUNT(*) + @total as registerNumber, @total FROM calendar c3 INNER JOIN ( SELECT c2.ide_calendar as ide_calendar, c2.name, DATE_FORMAT(i.date_creation, "%Y-%m-%d") as registerDate FROM calendrar c2 LEFT JOIN inscription i ON i.ide

What's the opposite of var-export function in php?

耗尽温柔 提交于 2021-02-16 21:27:18
问题 I export a variable to a textarea via "var_export($schools,true)" so user can edit it. Then I want to 'update' the variable with the changes made. The updates is received via POST method. I have some text that I want to become a variable . How can I do that? What I do right now is that I edit the variable manually in .php file. I want to give an web interface to users do to the same. There won't be no security issues as this will be strictly inhouse tool only. Sample of the variable $schools

Why does assignment operator call constructor?

天涯浪子 提交于 2021-02-16 15:55:28
问题 I am just playing around to understand smart pointers and trying to make mine but I come across a situation that I do not fully understand. Here is the code: #include <iostream> template <class T> class Holder { private: T * obj; public: Holder(T * tt) : obj(tt) { std::cout << "ctor : " << tt->dummy << std::endl; } T * operator -> () { return obj; } operator bool() { return obj; } T * const get() const { return obj; } void reset() {swap(0);} void swap(T * other) { obj = other; } Holder &

Assignment using get() and paste()

大憨熊 提交于 2021-02-11 16:57:01
问题 In my code I have to create an object assigning some values, something like this: assign(paste("a","bis",sep="."),rep(NA,5)) then I have to replace some of them, like this: get(paste("a","bis",sep="."))[1:2] <- 7:8 But I get the following error: "Error in get(paste("a", "bis", sep = "."))[1:2] <- 7:8 : target of assignment expands to non-language object". Of course the code above is a simplified version of the real one. What I'm trying to do is to build a loop which allows me to replace in a

How to resolve this compilation error “Using unassigned local variable 'hak'” when using goto?

女生的网名这么多〃 提交于 2021-02-11 12:34:57
问题 I'm trying below code. It gives me a warning "Use of unassigned local variable 'hak' ". I guess I'm missing something here. I want it to display " 3 defa yanlış giriş yaptınız. Müşteri hizmetleri temsilcisiyle görüşünüz. İyi günler dileriz. " when local variable "hak" equals to "0". But it always display " Hatalı Giriş Yaptınız. Lütfen tekrar deneyiniz. 2 hakkınız kalmıştır. " Console.Write("Seçmek istediğiniz 'Kullanıcı Adı'nı belirtiniz: "); string kullanici_adi = Console.ReadLine();

Fixing no return function for numpy.nextafter

别说谁变了你拦得住时间么 提交于 2021-02-10 18:48:39
问题 I'm trying to find the next floating point value after a towards a + 1 . My code basically looks like this: if a == 0: a = numpy.nextafter(a,a+1) I expect to get a new a that's the next floating point value, as stated above, but all I get is "Assigning result of a function call, where the function has no return (assignment-from-no-return)". I've double checked my versions of NumPy and Python, and cannot figure out what's wrong. 来源: https://stackoverflow.com/questions/54548783/fixing-no-return

Fixing no return function for numpy.nextafter

冷暖自知 提交于 2021-02-10 18:48:36
问题 I'm trying to find the next floating point value after a towards a + 1 . My code basically looks like this: if a == 0: a = numpy.nextafter(a,a+1) I expect to get a new a that's the next floating point value, as stated above, but all I get is "Assigning result of a function call, where the function has no return (assignment-from-no-return)". I've double checked my versions of NumPy and Python, and cannot figure out what's wrong. 来源: https://stackoverflow.com/questions/54548783/fixing-no-return

Feeding values to a Variable using feed_dict in TensorFlow

二次信任 提交于 2021-02-10 15:42:58
问题 I'm through https://www.tensorflow.org/get_started/mnist/pros . Reading "Note that you can replace any tensor in your computation graph using feed_dict -- it's not restricted to just placeholders," I tried to give values to a Variable using feed_dict as follows: print(accuracy.eval(feed_dict={x: mnist.test.images, y_: mnist.test.labels, W[:, :]: np.zeros((784, 10))})) However, it gave the original accuracy 0.9149 (I expected around 0.1). Can I give constant values to Variables after

Loading javascript in Code Igniter

 ̄綄美尐妖づ 提交于 2021-02-08 02:16:05
问题 For our Code Igniter application we are loading all of our javascript just before the closing body tag. so in our controllers we have $this->load->view('head', $this->head); $this->load->view('main_view_for_controller', $data); $this->load->view('foot', $this->foot); And in the foot view we have a bunch of <script src="master.js"></script> tags. These include jQuery jQuery-ui shared-functions Now this works great, until you think about JS used only on specific pages, or inline js. You can't

Loading javascript in Code Igniter

大兔子大兔子 提交于 2021-02-08 02:11:00
问题 For our Code Igniter application we are loading all of our javascript just before the closing body tag. so in our controllers we have $this->load->view('head', $this->head); $this->load->view('main_view_for_controller', $data); $this->load->view('foot', $this->foot); And in the foot view we have a bunch of <script src="master.js"></script> tags. These include jQuery jQuery-ui shared-functions Now this works great, until you think about JS used only on specific pages, or inline js. You can't