Get Job id and put them into a bash command

问题

Hello for a projet I need to execute a bash file only when all previous run have been finished so I use :

sbatch -d afterok:$JobID1:$JobID2:$JobIDN final.sh 

in Order to run the JobIDN I do

for job in Job*.sh ; do sbatch $job; done 

Then it prints all the jobIDs

I just wondered if someone haave a command in order to grab these IDs and put them directly to the command :

sbatch -d afterok:$JobID1:$JobID2:$JobIDN final.sh 

exemple

for job in Job*.sh ; do sbatch $job; done 
1
2
3


sbatch -d afterok:$1:$2:$3 final.sh 

回答1:

You can store the job ids in a variable and use it for your next command. Something like

jobs=$(seq 1 10 | awk '{ printf ":%s", $1 }')
     # \------/
 # your jobID printing function here

And then

sbatch -d afterok"$jobs" final.sh 

回答2:

You can do it with

for job in Job*.sh ; do sbatch --parsable $job; done | paste -s -d: | xargs -I{} sbatch --depedency afterok:{} final.sh

The paste command will gather all job IDS and write them on a single line, colon-separated, while xargs will take the result and insert it at the {} placeholder. The information about the job IDs is passed through pipes.

来源：https://stackoverflow.com/questions/62625865/get-job-id-and-put-them-into-a-bash-command