问题
My client sends me a date in "2019-11-22T16:16:31.0065786+00:00" format. I am getting the following error:
java.text.ParseException: Unparseable date: "2019-11-22T16:16:31.0065786+00:00"
The date format that I am using is:
new GsonBuilder().setDateFormat("yyyy-MM-dd'T'HH:mm:ss.SSSSSSSZ")
.create();
Please let me know which format to use.
回答1:
This format can be handled by DateTimeFormatter.ISO_ZONED_DATE_TIME instance of DateTimeFormatter
. It is a part of Java Time
package which was released together with 1.8
version. You should use ZonedDateTime
to store values like this but we can convert it also to obsolete Date
class.
import com.google.gson.Gson;
import com.google.gson.GsonBuilder;
import com.google.gson.JsonDeserializationContext;
import com.google.gson.JsonDeserializer;
import com.google.gson.JsonElement;
import com.google.gson.JsonParseException;
import java.lang.reflect.Type;
import java.time.ZonedDateTime;
import java.util.Date;
public class GsonApp {
public static void main(String[] args) {
Gson gson = new GsonBuilder()
.setPrettyPrinting()
.registerTypeAdapter(Date.class, new DateJsonDeserializer())
.registerTypeAdapter(ZonedDateTime.class, new ZonedDateTimeJsonDeserializer())
.create();
System.out.println(gson.fromJson("{\"value\":\"2019-11-22T16:16:31.0065786+00:00\"}", DateValue.class));
}
}
class DateJsonDeserializer implements JsonDeserializer<Date> {
@Override
public Date deserialize(JsonElement json, Type typeOfT, JsonDeserializationContext context) throws JsonParseException {
ZonedDateTime zdt = ZonedDateTime.parse(json.getAsString());
return Date.from(zdt.toInstant());
}
}
class ZonedDateTimeJsonDeserializer implements JsonDeserializer<ZonedDateTime> {
@Override
public ZonedDateTime deserialize(JsonElement json, Type typeOfT, JsonDeserializationContext context) throws JsonParseException {
return ZonedDateTime.parse(json.getAsString());
}
}
class DateValue {
private ZonedDateTime value;
public ZonedDateTime getValue() {
return value;
}
public void setValue(ZonedDateTime value) {
this.value = value;
}
@Override
public String toString() {
return "DateValue{" +
"value=" + value +
'}';
}
}
Above code prints:
DateValue{value=2019-11-22T16:16:31.006578600Z}
When you change ZonedDateTime
to Date
in DateValue
class it will print this date with relation to your time zone.
See also:
- java.util.Date format SSSSSS: if not microseconds what are the last 3 digits?
- Java Date toString contains a timezone… Why?
回答2:
The given pattern is "yyyy-MM-dd'T'HH:mm:ss.SSSSSSXXX"
. Please check https://docs.oracle.com/javase/7/docs/api/java/text/SimpleDateFormat.html
import java.text.ParseException;
import java.text.SimpleDateFormat;
import java.util.Date;
public class Task {
public static void main(String[] args) {
String pattern = "yyyy-MM-dd'T'HH:mm:ss.SSSSSSXXX";
SimpleDateFormat simpleDateFormat = new SimpleDateFormat(pattern);
Date date = null;
try {
date = simpleDateFormat.parse("2019-11-22T16:16:31.0065786+00:00");
} catch (ParseException e) {
e.printStackTrace();
}
System.out.println(date);
}
}
来源:https://stackoverflow.com/questions/58999880/correct-date-format-to-use-for-gsonbuilder-date-format