问题
I'm new to Python and having difficulty getting the output to print on one line.
This is pertaining to the online Python class Learning Python Essentials Lab 5.1.10.6 and printing to a 7-segment-device. If you are unfamiliar with a 7-segment-device, see Wikipedia.
I am NOT using any external device. I only need it to print to my own terminal. All the other StackOverflow solutions I found are related to using actual devices and didn't help.
Lab Link: https://edube.org/learn/programming-essentials-in-python-part-2/lab-a-led-display
Purpose: Prompt user for number; print number in 7-segment display format to your terminal.
- Notes: Using Python3.9. I tried 3 alternate solutions (Option 1,2,3), but none do what I want it to.
- INSTRUCTIONS: Un/Comment Option 1,2,or 3 to run just that option
- I did find this alternate solution, which I mostly understand. However, it's a totally different approach and not one I would have come up with. I know there are many ways to skin a 7-segment-device, and if this is the most correct, then I'll learn it. But I feel like I'm so close and only a superfluous
'\n'
away from figuring it out with my own method and trying to understand what I'm missing.
Thank you for your help.
Desired Output
### ## ### ### # # ### ### ### ### ###
# # ### # # # # # # # # # # #
# # ## ### ### ### ### ### # ### ###
# # ## # # # # # # # # # #
### ## ### ### # ### ### # ### ###
My Code
# clear screen each time you run the script
import os
clear = lambda: os.system('cls')
clear()
#
# Dictionary of (number:7-segment-hash)
dict1 = {
'0':('###','# #','# #','# #','###'),
'1':('#####'),
'2':('###',' #','###','# ','###'),
'3':('###',' #','###',' #','###'),
'4':('# #','# #','###',' #',' #'),
'5':('###','# ','###',' #','###'),
'6':('###','# ','###','# #','###'),
'7':('###',' #',' #',' #',' #'),
'8':('###','# #','###','# #','###'),
'9':('###','# #','###',' #','###')
}
# Function to print numbers in 7-segment-device format
def fun_PrintNums(num):
if num < 0 or num % 1 > 0 or type(num)!=int: # if num is NOT a positive whole integer
return "Invalid entry, please try again"
else:
display = [' ']
for i in str(num): # convert 'num' to STRING; for each "number" in string 'num'
#'''Option 1: works, but prints nums vertically instead of side-by-side; Return=None ''' #
for char in dict1[i]:
print(*char)
print(fun_PrintNums(int(input("Enter any string of whole numbers: "))))
#----------------------------------------------------------------#
#''' Option 2: Return works, but still vertical and not spaced out ''' #
# for char in dict1[i]:
# display.append(char)
# return display
# print('\n'.join(fun_PrintNums(int(input("Enter any string of whole numbers: ")))))
#---------------------------------------------------------------------#
#''' Option 3: 'display' row1 offset; spaced out as desired, but vertical; Return=None''' #
# for char in dict1[i]:
# display += char
# display += '\n'
# a = print(*display,end='')
# return a
# print(fun_PrintNums(int(input("Enter any string of whole numbers: "))))
#---------------------------------------------------------------#
Option 1 Output Works, but prints nums vertically instead of side-by-side; Return=None
# # #
#
# # #
#
# # #
# # #
#
# # #
#
# # #
None
Option 2 Output Return works, but still vertical and not spaced out.
###
#
###
#
###
###
#
###
#
###
Option 3 Output 'display' row1 offset; spaced out as desired, but vertical; Return=None
# # #
#
# # #
#
# # #
# # #
#
# # #
#
# # #
None
回答1:
Your problem is that you are printing each number before the next, but you need to print each row before the next. As a simplified example:
dict1 = {
'0':('###','# #','# #','# #','###'),
'1':(' ##','###',' ##',' ##',' ##'),
'2':('###',' #','###','# ','###'),
'3':('###',' #','###',' #','###'),
'4':('# #','# #','###',' #',' #'),
'5':('###','# ','###',' #','###'),
'6':('###','# ','###','# #','###'),
'7':('###',' #',' #',' #',' #'),
'8':('###','# #','###','# #','###'),
'9':('###','# #','###',' #','###')
}
num = '0123456789'
for row in range(len(dict1['0'])):
print(' '.join(dict1[i][row] for i in num))
Output:
### ## ### ### # # ### ### ### ### ###
# # ### # # # # # # # # # # #
# # ## ### ### ### ### ### # ### ###
# # ## # # # # # # # # # #
### ## ### ### # ### ### # ### ###
If you don't want to use a list comprehension inside join
, you can unroll that like this:
for row in range(len(dict1['0'])):
line = []
for i in num:
line.append(dict1[i][row])
print(' '.join(line))
来源:https://stackoverflow.com/questions/61809719/python3-print-on-same-line-numbers-in-7-segment-device-format