问题
I am using the R heatmaply
package to produce interactive heatmaps. I like the software, but I would like to get from it the same color output I get using the pheatmap
package. Therefore, I would like the two commands to produce the same ouput:
heatmaply (scale (mtcars))
pheatmap (scale (mtcars))
Is there a way to do this? Thanks in advance. Arturo
回答1:
You can use formals()
to get the default color argument of pheatmap()
.
formals(pheatmap)$color
# colorRampPalette(rev(brewer.pal(n = 7, name = "RdYlBu")))(100)
Then set the color argument of heatmaply()
to the same one:
col <- colorRampPalette(rev(RColorBrewer::brewer.pal(n = 7, name = "RdYlBu")))(100)
heatmaply(scale(mtcars), colors = col, grid_color = "grey60")
- The color function
brewer.pal()
is from theRColorBrewer
package, so you need to install and load it with::
orlibrary()
in advance. grid_color
inheatmaply()
is corresponding toborder_color
inpheatmap()
.
来源:https://stackoverflow.com/questions/61931334/r-heatmaply-and-pheatmap-output